Display embedded images in a HTML file!?

amycrystal123

Hi Guys,
I have been working on PHP/MySql for sometime now. I have created some programs that upload files from my computer and that stores the paths in the database table.

I am able to copy/move files and retrieve files back. I am able to retrieve my image and text files and plain HTML files.

But, my problem is this:::
When I retrieve my HTML file (whose path is stored in table), I am able to get them displayed on my web page. But, if the HTML page has image tags in it, the images embedded are not displayed INSTEAD I have the place allocated (based on the image's width and height BUT no image).

Please help me!

Thanks.
Amy.

yelvington

Images aren't embedded in HTML; the IMG tag points to a resource that must deliver the image. Sounds like you are pointing at an invalid URL.

Are you uploading images into the database? If so, have you written a program to retrieve and display them with the correct Content-type header? Does your HTML point to that script with the appropriate args?

amycrystal123

Hi,
Thanks for your response. yeah.. I've uploaded the image in the same folder as the HTML page. Now.. I am not sure.. where I need to make changes in the HTML tag and how to point to the script which would help the image to be displayed.

Pls give me an example.
Thanks.
Amy.

amycrystal123

The following is the code. I've the details of the file stored in an object and I retrieve all the file values from the database. The database table stores the file name, file type, file path, file size.

When I had uploaded the file, I copied/moved the file to another location and stored the file path and file details in the database (but not the file itself).

I am retrieving all the file values from the database to be displayed (files are in the types of either HTML, TXT or IMG). I am able to retrieve the files without any problems. I am able to display my HTML file, TXT file and IMG file but for the HTML files that contain a IMG file, that IMG file does not get displayed.

Sometimes - reason unknown: plain IMG files are not getting displayed.. and sometimes they do.. and that confuses me too!

So, I tried to create a program called getPicture.php that created a IMG header and returns the IMG file. I have the HTML file IMG SRC point to IMG SRC=getPicture.php?image1.jpg..

Please can you see where I am wrong.. Thanks for your help..
Amy.

The getPicture.php program is as follows:

<?php
/ About this page -
This page cannot be viewed by any user.
This page returns the image file.
/

if($image)
{
Header( "Content-type: image/jpeg");

//send the binary data
echo $image;
}
?>

The PHP program that displays all the files (retrieved from the database) is as follows::

<?php

//Start the session
session_start();

//Include the following class and php scripts.
include('MyFile.php');
include('MySqlConnection.php');
?>

<html>
<head>
<title>KCTS Events</title>
</head>
<body>
<?php
//Create an instance of the MyFile class
$newFile= new MyFile();

//Creates a database object using the MySqlConnection php script.
$db_connection = mysqlConnect();

//Retrieves all files
@ $result = mysql_query($newFile->selectAllFiles() ,$db_connection);

//If values could not be retrieved, prints error.
if (! $result)
{
echo " Error: Values could not be retrieved. ";
exit;
}

//For every file row from the database, gets the file attributes.
while($row = mysql_fetch_array($result))
{
$newFile->setFileName(htmlspecialchars(stripslashes($row['FILE_NAME'])));

$newFile->setFileType(htmlspecialchars(stripslashes($row['FILE_TYPE'])));

$newFile->setFileSize($row['FILE_SIZE']);

$newFile->setFilePath(htmlspecialchars(stripslashes($row['FILE_PATH'])));

$file = $newFile->getFilePath();

//Prints the file information.
echo $newFile->printFile()." ";

if ($newFile->getFileType() == "text/plain")
{
$fp = fopen($file, 'r');
$contents = fread ($fp, filesize ($file));
fclose ($fp);

$contents = nl2br($contents);
echo $contents;
}
elseif ($newFile->getFileType() == "text/html" || $newFile-getFileType() == "text/htm")
{
include ($file);
}

elseif ($newFile->getFileType() == "image/pjpeg" || $newEvent->getFileType() == "image/gif")
{
echo "<img src=getPicture.php?$file > ";
}

}
?>
</body>
</html>