Reading Unknown Folders

[rapmonkey]

Hi, I need to read data from folders that I don't know are there...For example, the user creates a folder in the directory to read from and the script detects all the folders they created in that one folder. Example:

In FOLDER/ I have two sub directories, ONE and TWO. The script needs to read all the folders within the FOLDER/ directory (in this case ONE and TWO) and display them. How would I go about doing this? Thanks!

[LordShryku]

[man]opendir[/man]
[man]readdir[/man]
[man]is_dir[/man]

Check those out. Pay mind to the user comments...

[rapmonkey]

Thanks, that really helped! However, it has two small problems. It lists files, as well as directories (I just want directories) in the array. And two, it echos the directories like so:

Array
(
[2] => SKIN_ONE
[3] => SKIN_TWO
[0] => background.gif
[1] => header_dark.gif
)

My guess is that (assuming it only reads the directories) I would have to count the length of the array and echo them in a for loop?

[LordShryku]

That's where is_dir comes in handy. Show me what you're doing and I can hel pyou out...

[rapmonkey]

I'm just testing out the function that a user posted:

function get_dirlist($dir)
{
  $dirlist=array();

  $dh=opendir($dir);
  if ($dh)
  {
   while ($filename=readdir($dh))
   {
     if (!is_file($filename) and !is_dir($filename))
     {
       $dirlist[]=$filename;
     }
   }
   closedir($dh);
  }
  else
  {
   return false;
  }

  asort($dirlist);
  return $dirlist;
}
$testdir = get_dirlist("directorytocheck");
echo "<pre>";
print_r($testdir);
echo "</pre>";

I want it to echo the directory names, and only the directories, one by one.

[LordShryku]

Well, the one line I can see needing changed is this one:
if (!is_file($filename) and !is_dir($filename))

It's saying only if it's not a file and not a directory would you use it. You'd want to do this instead:
if(!is_file($filename) && is_dir($filename))

And it's specified to return an array, so to echo them, just loop through the array.

[rapmonkey]

The same script with that modification now displays this:

Array
(
[0] => .
[1] => ..
)

[LordShryku]

Well....those are valid directories. Do you have more in there? Maybe take out the is_file check...

[rapmonkey]

I want the script to display the NAMES of the directories not the locations. For example, say I'm searching in "mydir". The subdirectories in "mydir" are "ONE" and "TWO". I don't want it to say "." and ".." I want it to say "ONE" and "TWO".

[LordShryku]

. and .. ARE directory names. Do an ls -al in a directory, any directory, and those will come up. They are the names for "current directory" and "previous directory".

[rapmonkey]

I mean if the directory name is "TWO" I want "TWO" displayed, not some dots, even if they are real names. This is crucial because the user needs to know the directory name in order to understand what is in its contents.

[LordShryku]

Did you try removing the is_file check like I suggested a couple posts ago?

[rapmonkey]

Taking out these lines:

 if (!is_file($filename) && is_dir($filename))
 {
   $dirlist[]=$filename;
 }

Results in this being displayed:
Array
(
)

[LordShryku]

function get_dirlist($dir) {
   $dirlist = array();
   $dh      = opendir($dir);
   if($dh) {
      while(false !== ($filename=readdir($dh))) {
         if(is_dir($filename)) {
            $dirlist[]=$filename;
         }
      }
      closedir($dh);
   }
   else {
      return false;
   }
   asort($dirlist);
   return $dirlist;
}

$testdir = get_dirlist("directorytocheck");
echo "<pre>";
print_r($testdir);
echo "</pre>";

[rapmonkey]

Array
(
[0] => .
[1] => ..
)

[LordShryku]

Well...it doesn't see those directories. You sure you're passing it the right directory to read?

[rapmonkey]

Yes, a fake directory displays an error: Warning: opendir(blah): failed to open dir: No such file or directory

[LordShryku]

Then I don't know what to tell you. It doesn't see those as directories, or it's in the wrong directory. I just did this in my web root, and it returned all of my directories fine.

<?php
function get_dirlist($dir) {
   $dirlist = array();
   $dh      = opendir($dir);
   if($dh) {
      while(false !== ($filename=readdir($dh))) {
         if(is_dir($filename)) {
            $dirlist[]=$filename;
         }
      }
      closedir($dh);
   }
   else {
      return false;
   }
   asort($dirlist);
   return $dirlist;
}

$testdir = get_dirlist(getcwd());
echo "<pre>";
print_r($testdir);
echo "</pre>";

[rapmonkey]

Perhaps it is the wrong directory...This is my situation. The script is running as an include. The file calling it is in / and the script being called is in /forms. I need to get the list from /images/skins. What directory would I specify?

[LordShryku]

You'd just call the directory in the function. But make it the absolute path, not the releative path. So it your web root is in /home/rapmonkey/public_html, you'd use

$testdir = get_dirlist("/home/rapmonkey/public_html/images/skins");