Sort of a PHP question

[Swedie]

Hey I am having issues with a form box.

This works like a charm:
<input type="submit" name="action" value="Add Site">

But this doesn't work:
<input type="image" src="addsite.gif" name="action" value="Add Site">

What I want to do is replace the button with an image. But it don't seem as if the "action" value is sent through the browser.

Or is there a special method for picking up the value? I mainly just do "if($action == "Add Site") { dowhateva }"...

please help me solve my problem.

thanks

[sfullman]

I'm thinking you want to do various actions depending on which button is clicked,

Got this from one of my sites:

<input type="image" border="0" name="imageField" src="../images/assets/checkout.gif" width="241" height="27" alt="Click here to check out" value="add" onClick="whichAction.value=this.value;document.form.submit();">

<!-- need this hidden field in the form -->
<input type=hidden value="" id="whichAction" name="action" value="">

This will set the hidden field's value to 'add' when you click on that particular button.

Sam

[swr]

Check for action_x and action_y instead of action.

I believe this is for server-site clickable image maps, so you can do different things depending on where on the image the person clicked.