[Resolved] outputting directory contents with full path?

[stephdumais]

Hi, I have this code snippet which works fine:

$files = array();
$open = opendir($currentpath);
while ($file = readdir($open)) { if ($file != "." && $file != "..") { $files[] = $file; } }
closedir($open);
sort($files);
reset($files);

This outputs an array with the contents of $currentpath directory. However, I'd like to re-use the above for another function where I could display the full paths for each of the outputted elements.

Any suggestions how I could do this? Maybe it's simpler than I think but I really dont see right now 🙁

thanks

[stephdumais]

Ok I figured out a logic to this but I'm still unsure of the syntax to use.

Based on the code above, what I want is to create an array where the value of $currentpath is prepended to each element of the original array.

So if $currentpath is "../"
The original array would produce:
("dir1","dir2","dir3")

and I want a new array which would be:
("../dir1","../dir2","../dir3")

How do I insert $currentpath into the array for each element?

[cosminb]

try this:

<?php
$files = array();
$open = opendir($currentpath);
while ($file = readdir($open))
{
  if ($file != "." && $file != "..")
  {
   $files[] = realpath($curentPath).DIRECTORY_SEPARATOR.$file; 
  }
}
closedir($open);
sort($files);
reset($files);
?>

[stephdumais]

Excellent, this is what I've been looking for. Thanks!

[cosminb]

😃 glad to help