PHP Gallery Idea, N00b

Chadian22

----- I posted at another forum, but havn't recieved any help. I am dedicated to figuring this out, its a learning experience.

http://www.phpfreaks.com/forums/index.php?act=ST&f=12&t=16483&st=0#entry60151

yelvington

Maybe you should post the code here. I'll do it for you.

<?
$dir = "."  ;
if (is_dir($dir)){
if ($dh = opendir($dir)) {
    while (($file = readdir($dh)) != false); {
        if filetype($file = "*.jpg") {
            print $file; }
               }
              }
           }
       }

?>

PHP is complaining about line 6. What is on line 6? An if() whose conditions are not enclosed by parentheses.

Even after you fix that error, you will never print anything. Why? Hint: Semicolons terminate statements. Look at line 5.

Chadian22

Yah you're right. I fixed the formatting.

<?
$dir = "."    ;
if (is_dir($dir)){
	if ($dh = opendir($dir)) {
    	while (($file = readdir($dh)) != false); {
        	if (filetype($file = "*.jpg")) {
            	print $file ;}
                }
               }
            }

?>

which simply outputs> *.jpg
I knew there was something w/ my filetype function, when i was reading the PHP manual , it says jut returns if the filetype is a file or folder. Not quite what I wanted it to do

yelvington

Actually, filetype() "Returns the type of the file. Possible values are fifo, char, dir, block, link, file, and unknown." In any case, what this function regards as "type" is not what you are looking for.

You could use strstr(), but it will return a match on "foo.jpg.txt" and that's not what you want either.

You need to test if the filename ends in '.jpg'. Use a regular expression:

if ( preg_match( '/.jpg$/', $file) ) print $file;

Chadian22

Ok, thanks, i did what you suggested.

Using the following code

<?

$dir = "."    ;
if (is_dir($dir)){
	if ($dh = opendir($dir)) {
    	while (($file = readdir($dh)) != false); {
        	if ( preg_match( '/\.jpg$/', $file) ){
            	print $file ;}
                }
               }
            }

?>

i get the result > http://chadian22.no-ip.com/gallery/ . a blank page...
It should look through the file variable, if it finds the .jpg in any of the file name string located in $file, it should print the file.... then it should continue the loop as long as there is something to read... Im confused, but Im learning =) and it is fun =P

Oh yah, I forgot to add some files in there. But I did now. Still not working.

Chadian22

So i figured it out, thanks to 'yelvington' for all his help! , im on the right tract. Its downhill from here hopefully, maybe ill post further about my gallery and submit a final code once it all works.

Chadian22

So with the help of others, I accomplished finding jpegs and then i split the jpeg string, if it were chadian22.jpg, to load a chadian22_sm.jpg the sm= small, for the thumbnial, then there would be a link to the big one with the source of the link being the thumbnail. But i didnt want to make to filter through and resize it myself. so i developed the following code. Edit |||| Oh yah, I forgot, ignore some of my comments, some of them are just research i did on php.net but the funtion didnt end up getting used in the end , it was just there if I needed it for something, and for learning how its all put together. |||||

<?
$number = 0 ;// counter starting at 0
$nrow = 4 ;// amount of thumbnails per row
$dir = "."    ;
if (is_dir($dir)){
	if ($dh = opendir($dir)) {
    	while (($file = readdir($dh)) != false) {
                if ( preg_match( '/\.jpg$/', $file) ){
                	if ((preg_match( '/\_sm.jpg$/', $file)) != true){
                  		  $jpegname = str_replace(".jpg", "", $file);

            	      if ((is_file($jpegname."_sm.jpg"))== false){

                       // $size = getimagesize($jpeg)
					 //thanks to [url]http://www.onlinetools.org/articles/creating_thumbnails_all.php#The%20logic%20of%20batch%20processing%20thumbnails[/url] for resize dimensions code
                     $old_x=imageSX($file);
					 $old_y=imageSY($file);
					 if ($old_x > $old_y) {
				     $thumb_w=$new_w;
				     $thumb_h=$old_y*($new_h/$old_x);
					  }
	   				   if ($old_x < $old_y) {
  					  $thumb_w=$old_x*($new_w/$old_y);
					     $thumb_h=$new_h;
					    }
					   if ($old_x == $old_y) {
					      $thumb_w=$new_w;
				      $thumb_h=$new_h;
					    }
                      $dst_img=ImageCreate($thumb_w,$thumb_h);
   					  imagecopyresized($dst_img,$src_img,0,0,0,0,$thumb_w,$thumb_h,$old_x,$old_y);
                      imagejpeg($dst_img,$file."_sm.jpg");


                    }


       			     echo "<a href=\"$bpic\"><img src=\"$file\"></A>" ;




                    if ($number == $nrow) {   //if the max # of pics, then <BR>
                	echo "<br>";
                    $number = 0 ;
                    }
                else {
                $number++  ;
                }

            }
            }
           }
        }
// $domain = stristr($email, 'e');
//                     $spic = "_sm" ;
//					$bpic = str_replace($spic, "", "$file") ;
?>

I get the Error : Parse error: parse error, unexpected $ in C:\FoxServ\www\gallery\gather.php on line 65

-- I think there's more errors, but I really cant figure out what the error is so I can debug the rest of the thing. Line 65 is after the last ?> and its just blank space, how's this possible 😕 Thanks for all the help! THis is my first major code.

ajdegans

Is the error in the last post solved? that it keeps coming up on parse errors outside the php code?