PHP increment counter help

pbjpb

i'm a PHP beginner and i have this PHP code that increments a number:

<?php
$fp = fopen("/usr/local/counter.txt", "r+");
flock($fp, LOCK_EX);
$now = fgets($fp, 10);
$now = intval($now)+1;
fseek($fp, 0, SEEK_SET);
fputs($fp, "$now");
flock($fp, LOCK_UN);
fclose($fp);
?>

it works incrementing but i need the word "counter=" in front of the number when it's printed to the text file. i tried changing this line:

fputs($fp, "$now");

to:

fputs($fp, "counter=$now");

but it stopped the incrementing. anyone have any ideas? thanks!

swr

The problem is that "counter=1" is not a number, so it gets interpreted as 0 when you do math on it, which means your counter will always get set to 1 (0+1 = 1).

If you could get by that, you're telling fgets to not get more than 10 characters, 8 of which will be "counter=" so if your number is larger than 99 you'll only get the first two digits.

Try this:

$now = fgets($fp);
$now = substr($now, strpos($now, "=") + 1);
$now = intval($now)+1;

The substr/strpos thing gets everything after the = in the string. See the manual pages for [man]substr[/man] and [man]strpos[/man] for details.

pbjpb

thanks swr!

that worked! everything is working perfectly now, thanks again!