[Resolved] opendir() loop question

[helz]

I have a script that opens a directory and lists the files,
in the if statement that i use to get rid of the . and .. directories
i have it setup so it ignores a specific file in the directory.
It has come to the time that i want to add another file into the
directory and i want it to be ignored by the script, i had an idea
of replacing the specific file with a wildcard but it failed to work...

This is what i had:

if ($file!="." && $file!=".." && $file!="thumbnail.php" ){

This is what i had in mind to do instead:

if ($file!="." && $file!=".." && $file!="*.php" ){

but it displays the file i wanted it to ignore... is there a special thing
that i need for this task?

[LordShryku]

Well, there's a couple easy ways to do this. If you just want to ignore .php files, do this:

if ($file!="." && $file!=".." && substr($file,-4)!=".php" ){

That will just ignore the .php extension files. But say you only want to ignore some files. Put them in an array, then look for that.

$iggy = array("file1.php", "file2.blah", "file3.inc");
/* code, code, code */
if ($file!="." && $file!=".." && !in_array($file,$iggy)){

HTH

[helz]

nice

so the first one gets the filename of the current file. changes it so only the last 4 chars are displayed. (full stop and 3 extension chars) and then uses the extension to test to see if it is the file extension that wants to be ignored...

ta