problem with if/else statements

Hi all,

I'm having trouble with some if/else scripting...

on my local server, running PHP 4.3.2 on a WinXP Pro system, the following code works perfectly:

<?php if ($done == 'add') : ?>
 Thank you.  Your property has been successfully added<br /><br />
<?php endif ?>

However, when I upload this page to my webserver running PHP 4.3.4 on a Linux server, this same code does not work...HELP!!

The same goes for the following code:

<?php if ($row_rsDeleteProperty['propertyRef'] === "$propertyRef") : ?>
some code here
<?php endif ?>

Can anyone help me out here? Why does it work on one server, but not on another?

Peter

The problem here is that it is impossible to pinpoint any particular problem.

Maybe $done should be $_POST['done'] ?

Maybe the code associated with $row_rsDeleteProperty['propertyRef'] was poorly coded and just happened to work on a particular platform?

Maybe $propertyRef depends on something not available on the new platform?

Rather, test with small examples to reduce the number of variable factors.

e.g. to test for alternative syntax for control structures:

<?php
$test = 1;
if ($test == 1):
	echo 'test ok';
else:
	echo 'test failed';
endif;
?>

try to use this one

if $x=="add') {

your code here

}
else

{
your code here
}

forgot some characters here is the exact code

if ($x=="add") {

your code here {
else
{
your code here

}
?>

Well, janoy, paliz apparently wants to use the alternative syntax for control structures.

That syntax does have its advantages.

Thanks laserlight & jannoy!!

After testing your various methods, I found the code that works:

<?php if ($HTTP_GET_VARS['done'] == 'add') : ?>
 Thank you.  Your property has been successfully added<br /><br />
<?php endif ?>

and

<?php if ($_POST['propertyRef'] == "$propertyRef") : ?>
some code here
<?php endif ?>

Thanks!

Peter