checkbox +redisplay

Marcusanthonius

interesting but to hard for me...

i have a form with regular expressions.
it also contains a few checkboxes.

when a person checked some optional checkboxes, but made a mistake in the mandatory fields, the checkboxes become unchecked again. (that's my problem, probable more people got the same problem)
That person has to check them again, which is frustrating.

Which clever programmer knows how i can change my form?
Do I use the function isset() ?
Can I do this without cookies?

<input type="checkbox" name="changing_names" value="on">
<input type="submit" value="send" name="verzendbutton">
after submitting, my values are unchecked again...

Thanks sofar.

nemonoman

You need to add some code to your program when the page is redisplayed after the submit:

<input type="checkbox" name="changing_names" value="on"

<? if ($_POST['changing_names']) {echo " checked";} ?>

if the checkbox was not checked during submit, then $_POST['changing_names'] will be null.

Marcusanthonius

Thanks for answering,

but I think you don't understand what I meant.
I don't want to display the word 'checked' , what happened when I use your script,
I just want them to stay checked as long as a submitter makes mistakes in the form.
so checkbutton is checked visually 'after' submitting.
until the submitter has filled in 'the enire form' correctly.

maybe someone can send me the right answer with and without an array. (for rookie and novice)

thanks.

nemonoman

<input type=checkbox checked>
Should produce a checked checkbox

If you are seeing the word checked, you haven't placed the word checked within the html tags.

My code shows how to place the word checked within the tags.

Marcusanthonius

Yes, it did. It works very well.

for people who are using an array for the same problem, i found this (later) in this forum:

http://www.phpbuilder.com/board/showthread.php?s=&threadid=10270028&highligh

And so i have finished my search and my form...

Thanks, nemonoman !