Get the source of a remote file

easethan

hey, I'm trying to assign the output of a remote php file toa php variable and then parse it to find the info I need.

Any way to do this?

easethan

Resolved

Weedpacket

That's nice to hear; care to tell us about it?

phpprogrammer

Dear friend easethan,

could you tell how u did it if possible plz give the source code

regards
bvsureshbabu

swr

Heh... From what I've seen on this board, this kind of thread usually follows with a post of sample code, then another post about about how it violates the target website's terms of service, then the thread disappears. Then the process repeats again later in a new thread.

It's like a phantom FAQ. :p

easethan

lol @ swr, this won't end that way because I'm using one of my site's, I'm just trying to find info about game servers, the info is on another page though, and I don't wanna go through that page(open source program) and find out how it gets the info, so I'm doing it this way.

anyways,

<?php

$site = file("PAGE_TO_BE_LOADED");
$text = implode("", $site);

$ser1 = ereg("chief</a></td>\n<td>Online</td>", $text);
$ser2 = ereg("iceman</a></td>\n<td>Online</td>", $text);
$ser3 = ereg("Squad CSi</a></td>\n<td>Online</td>", $text);

if($ser1 == TRUE) {
$server1 = "1";
}
if($ser2 == TRUE) {
$server2 = "1";
}
if($ser3 == TRUE) {
$server3 = "1";
}

$serversnum = $server1 + $server2 + $server3;

echo $serversnum;

If there is a more efficient way to do this I would be very thankful, especially if you could make it to where the servers(chief, iceman, Squad CSi) don't have to be listed in this code, so I wouldn't have to update it every time we add a server.