Variable variable

[Benpsycho]

Why isn't this working?

		
$i=3;
$test{$i} = "TESTING";
echo $test3;

shouldn't it output TESTING?

[rebelo]

It's going into an array.

echo $test[3]; // prints TESTING

[Weedpacket]

Originally posted by Benpsycho

		
$test{$i}

[/B]

You mean

${'test'.$i}

- build a string and use it as the name of a variable.