Sending Images (Interesting Problem)

[Nixon]

Hey Guys,

What would be the best way to go about sending image files from one server to another. My point being I want to have people upload images and then when the image is upoaded I want to create a cron job to send to the pictures to a special image server. Any ideas?

Thanks. Jack

[drew010]

my idea would be to do something like read the contents of the file into a variable, compress and encode it and pass it to a script of the other server.

$data = file_get_contents($FILES['userfile']['tmp_name'];
$name = $FILES['userfile']['name'];

$data = gzcompress(base64_encode($data));

file("http://www.server2.com/storeimage.php?data=$data&name=$name");

--storeimage.php--

$filedata = $GET['data'];
unset($GET['data'];

$fp = fopen("./" . $_GET['name'], "w+");
fwrite($fp, base64_decode(gzdecompress($filedata)));
fclose($fp);

if you have questions, let me know.

p.s. check to make sure its really an image and there isnt a file with the name already there cause it will be overwritten.

[Nixon]

Here is my image checking code:

session_start();

if ($photo1 != "none" or $photo2 != "none" or $photo3 != "none" or $photo4 != "none" or $photo5 != "none" or $photo6 != "none")

{

$i=0;
$numphotos=0;
$imageno=1;
$array=array();

while ($i<6)

{

$i++;

$photo=photo;
$photo.=$i;

if ( is_uploaded_file ( $HTTP_POST_FILES[$photo]['tmp_name']) ) {

$imagetype=$HTTP_POST_FILES[$photo]['type'];

if($imagetype=='image/pjpeg' || $imagetype=='image/gif') {}
else { $error="One or more of your image types were unsupported"; }

$array[$imageno] = $$photo;

$imageno++;
$numphotos++;

}

}

}

else {$empty="Y";}

Then it uploads it ot where it should go:

include("includes/connectdb.php");

if ($error==NULL) 

{

$timestart=time();

mysql_query("	insert into classifieds

(				status, title, guitar, price, timestart, timeend, condition, tremlo, yearmade, serialno, 
				countryorigin, originalparts, necktype, description, postageprice, postageservice, 
				postalinsurance, collection, userid, link1, link2, link3, link4) 

			values 

			('1','$title', '$guitar', '$price', '$timestart', '$duration', '$condition', '$tremlo'
			, '$yearmade', '$serialno', '$countryorigin', '$originalparts', '$necktype', 
			'$description', '$postageprice', '$postageservice', '$postalinsurance', 
			'$collection', '$userid', '$linkarray[1]', '$linkarray[2]', '$linkarray[3]', '$linkarray[4]') ") 

			or print ( mysql_error() );

if ($empty!="Y") {

$info=mysql_query("select * from classifieds where title='$title' and price='$price' and description='$description'");

while ($row=mysql_fetch_array($info))

{

$classid=$row[id];

}

$i=0;

$imagepath="C:/phpdev/www/templatesite/ftpupload/$classid/";

while ($i<=$numphotos)

{

if ($i==0 ) { mkdir("$imagepath", 077 ); }

move_uploaded_file( $array[$i] , "C:/phpdev/www/templatesite/ftpupload/$classid/$i.jpg");

$i++;

}

$photo="insert into classphotos (id, numphotos";

$i=1;

while ($i<=$numphotos)

{

$photo .= ",photo";
$photo .= $i;

$i++;

}

$photo .= ") values ('";
$photo .= $classid;
$photo .="','";
$photo .= $numphotos;
$photo .="'";

$i=1;

while ($i<=$numphotos)

{

$photo .= ",'";
$photo .= $imagepath;
$photo .= $i;
$photo .= ".jpg";
$photo .= "'";

$i++;

}

$photo .= ")";

mysql_query("$photo") or die (mysql_error() ); 

}

}

else { print "<script> location.href='listguitar.php?error=$error' </script>"; die("$error"); }

How would I go about implementing it?

Thanks. Jack.