What's wrong?

[dstonek]

I intent to get words with at least one number and one other character. $string is an example.
I cannot find the error. Thanks.

$numbers = array(0,1,2,3,4,5,6,7,8,9);
$num = 'no';
$let = 'no';
$string = 'aje2903';     

$len = strlen($string);        

for ($i=0; $i<= $len-1; $i++)
    {           

       if (in_array($string{$i}, $numbers))       

         {         

$num='yes'; print $string{$i} . ' is number, ';                             }           

       if (!in_array($string{$i}, $numbers))
         {           

$let='yes'; print $string{$i} . 'is letter, ';
         }
    }     

 //a is number, j is number, e is number, 2 is number, 9 is number, 0 is number, 

[/SIZE]

[LordShryku]

Hrmmm....seems kinda unneccesary to me. Why not just use [man]is_numeric[/man]?

$num = 'no';
$let = 'no';
$string = 'aje2903';
for($i=0;$i<=strlen($string)-1;$i++) {
   if(is_numeric($string{$i})) {
      $num='yes';
      print $string{$i} . ' is number, ';
   }
   else {
      $let='yes';
      print $string{$i} . ' is letter, ';
   }
}

Probably the reason it's not working is because of the type. It's reading through a string instead of numbers. So your way would work if you converted your number array to string types.

$numbers = array('0','1','2','3','4','5','6','7','8','9');