[Resolved] Using 'var' made errors... What?

[ComputerNerd888]

Hello,

When I declare a variable (for the first time), I have always used the 'var' keyword, but I was just trying to test out a script I made and was getting errors on all of the 'var's used. When I removed them the errors are removed.

The scripts works with out them, but I hate making code with out them...

How could I fix this error...

Example:

function test()
{
    var $test;
   $test = mysql_connect();
}

That would result in the error:

Parse error: parse error, unexpected T_VAR in /home2/bgame/public_html/TEST/funcs.php on line 11

[/b]

but

function test()
{
    $test;
    $test = mysql_connect();
}

What could this be?

Andrew

[drew010]

var is for use with php classess and defining the variables within them. there is no need to declare variables in php. if you want to you can do it like this:
(string)$variable;
(bool)$variable2;
just put the type in the paranthesis and then the variable name.

[ComputerNerd888]

I know, but I have all ways used var to declare variables. I come from C/C++ and try to keep things like that (even if I don't have to) the same between so I don't have bad practice in either language.

Way now, but never before am I getting these errors?

Andrew

[Weedpacket]

Originally posted by ComputerNerd888
I know, but I have all ways used var to declare variables. I come from C/C++ and try to keep things like that (even if I don't have to) the same between so I don't have bad practice in either language.

Way now, but never before am I getting these errors?

Who knows? It's never worked like that. Have you got any that does? (It usually makes more sense to program in each language in its own idiom - it helps reduce errors caused by using the wrong language's syntax. You wouldn't code in C in the style of Lisp, would you?)

[laserlight]

I know, but I have all ways used var to declare variables. I come from C/C++ and try to keep things like that (even if I don't have to) the same between so I don't have bad practice in either language.

You do realise that the statement you have just made is absurd?
Think about it, the code you just gave doesnt work in C++ either.
(var isnt even a valid native keyword in C++, as far as I know).

function test()
{
	var $test;
	$test = mysql_connect();
}

int main()
{
	test();
	return 0;
}

I attempted to compile the above code in g++ 3.2 (MinGW) under Dev-C++.
The compile log shows:

Compiler: Default compiler
Executing g++.exe...
g++.exe "C:\projects\temp.cpp" -o "C:\projects\temp.exe" -I"C:\DEV-CPP\include\c++" -I"C:\DEV-CPP\include\c++\mingw32" -I"C:\DEV-CPP\include\c++\backward" -I"C:\DEV-CPP\include" -L"C:\DEV-CPP\lib"
C:/projects/temp.cpp:1: parse error before )' token C:/projects/temp.cpp:4: ISO C++ forbids declaration of$test' with no type C:/projects/temp.cpp:4: mysql_connect' was not declared in this scope C:/projects/temp.cpp:5: parse error before}' token C:/projects/temp.cpp: In function int main()':
C:/projects/temp.cpp:9:test' undeclared (first use this function) C:/projects/temp.cpp:9: (Each undeclared identifier is reported only once for each function it appears in.) Execution terminated

And I shall quote you:

Way now, but never before am I getting these errors?

[drew010]

function test()
{
var $test;
$test = mysql_connect();
}
isnt c++ code either, and there is no mysql_connect(). also c++ doesnt use $ for variables or have a function keyword, so of course it wont compile.

it would have to be more something like this

#include <cstdio>

using namespace std;

void test()
{
    char *test;
    test = "something";
    printf(test);
}

int main()
{
    test();
}

i think he was more saying he declares variables in php as good practice because its manditory in c++, not that he declares variables in c++ using var.
C++ requires all variables be declared before use with their data type.

and for ComputerNerd888 if you have always used var in php to declare variables, i dont know what to tell you about why it doesnt work now, i tried it and i got a parse error, i thought it was only for classes. if you do want to declare your variables, you can do it how i showed before
(int)$number;
(double)$value;
(string)$word;
(bool)$flag;
$list = array();
etc...

[ComputerNerd888]

Originally posted by drew010

i think he was more saying he declares variables in php as good practice because its manditory in c++, not that he declares variables in c++ using var.
C++ requires all variables be declared before use with their data type.

Thank you drew010 for not taking it so litteraly... PHP code will never compile as C/C++... Drew010 you are right, in C/C++ you must declare the type of varable (its strong typed), so if I were programing in PHP for a while and than swicthed to a C/C++ project, I will remember to define it. Normaly I would but this could result in less errors.

mysql_connect() could be a function in C/C++, actully it would be implmented that exact (close) way PHP did, (if you wanted to)...

Also if you were in C++ (or OO C) you could declare varables as 'var' if you made a 'var' class...

Thank you for the help of which I got,
Andrew