How to get full url (http://) with $_SERVER?

[tjitte]

Hello PHPbuilders,

Can someone tell me how I can get the full url from the server.

This is what I need as a result of the function (standard):
http://www.somedomain.com/

Reason:

I need to determine if the person is on the [url]http://[/url] or the [url]https://[/url]

Some tests (I allready check phpinfo)
<?php
echo $SERVER["HTTP_REFERER"] ."1<br>";
echo $SERVER["PHP_SELF"] ."2<br>";
echo $SERVER["HTTP_HOST"] ."3<br>";
echo $SERVER["DOCUMENT_ROOT"] ."4<br>";
echo $SERVER["SCRIPT_FILENAME"] ."5<br>";
echo $SERVER["REMOTE_ADDR"] ."6<br>";

echo $_SERVER["PATH_TRANSLATED"] ."7<br>";

   if (!isset($_SERVER['REQUEST_URI'])) {
       $_SERVER['REQUEST_URI'] =   $_SERVER['SCRIPT_NAME'].'?'.$_SERVER['QUERY_STRING'];
   }

   echo $_SERVER["REQUEST_URI"] ."8<br>";

    $get = explode("/",getenv("HTTP_REFERER"));    

     print_r($get);
     echo $get[2]. ."9<br>";   

?>

If you know the answer I will love you forever (duhhh)

That's all

Ciao!

Tjitte

[Kudose]

$_SERVER['HTTPS']

[tjitte]

code:
<?
echo "1" . $SERVER["HTTP_REFERER"] ."<br>";
echo "2" . $SERVER["PHP_SELF"] ."<br>";
echo "3" . $SERVER["HTTP_HOST"] ."<br>";
echo "4" . $SERVER["DOCUMENT_ROOT"] ."<br>";
echo "5" . $SERVER["SCRIPT_FILENAME"] ."<br>";
echo "6" . $SERVER["REMOTE_ADDR"] ."<br>";
echo "7" . $_SERVER["PATH_TRANSLATED"] ."<br>";
?>

result:

1. empty
2. /index2.php
3. www.somedomain.com
4. /usr/local/psa/home/vhosts/somedomain.com/httpdocs
   5./usr/local/psa/home/vhosts/somedomain.com/httpdocs/index2.php5
5. ip
   7./usr/local/psa/home/vhosts/somedomain.com/httpdocs/inde4. x2.php7

So not the result i'm looking for!!

[mrhappiness]

check $_SERVER['HTTPS'] for both your http and your https adress

[tjitte]

Thank you! this is what I need!