[RESOLVED] preg question

[palpie]

I'm trying to to use preg_replace to find a string in a text and then replace it using a separate variable (array).

If it finds the text %REFERENCE>> maps% for example, it should replace it with an url to the document maps - <A HREF="maps.php">kartor</A>. I want the word "kartor" to be taken from a dictionary array.

Is this possible in the way I've done here (but with modification of cource):

$output = preg_replace("/%REFERENCE>> (.+?)%/i", "<A HREF=\"\\\\1\">".$dictionary["menu"]["\\\\1"]."</A>", $input);

??

Or does anyone have any better ideas?

[poison]

it is
although I would write something more easily readable as reference (except your really messing with latex/PDF code 😉 ) like:

<%ref:test%>

and, finally I would use an array which already contains completely constructed links so you have a title for your link and not the link as title...

// <%ref:test%>
$out=preg_replace('/<\%ref\:([^\%]+)\%>/ieU', "\$links['menu']['\$1']", $in);

regards =D

[palpie]

It worked fine, thanks!