Ugh, help with dates

[Rulkster]

Hi, I need help adding two dates together in php. I've done research here, but it has just confused me further.

I am grabbing the first date from a database. This date can be anything: (as an example: $first_date = 2004-04-24).

Now i only know the number of days to add to this date. Say it is 7 days. In english:

$first_date = $first_date + 7 days

or

2004-04-24 + 7 days = 2004-05-01

Thanks for any help.

Brian

[m_tt]

I'm sure there is an easier method but you could do something like this:

$first_date = "2004-04-24";
	list($year,$month,$day) = explode("-", $first_date);

$next_date = date("Y-m-d", mktime(0,0,0,$month,$day+7,$year));

echo $next_date;

[yid]

I'm not sure if mktime will handle day rollovers and leapyear correctly or not...

However, Pear's Date package makes this very easy.

http://pear.php.net/package/Date/1.4.2

<?php
require_once("Date/Calc.php");

$first_date = "2004-04-24";
$add_days = 7;
$format='%Y-%m-%d';

list($year, $month, $day) = explode("-", $first_date);

//convert date to days since epoch
$days = dateToDays($day, $month, $year);
//add some days, and then convert days since epoch to date
$next_date = daysToDate($days+$add_days, $format);

echo $next_date;
?>

I encourage you to check out all the useful functions in the Date package; I think you'll find it very useful.

note: This sourcecode is neither tested nor guaranteed.

HTH
yid

[devinemke]

even simpler:

$date = '2004-04-23';
$date_plus_7 = date ('Y-m-d' , (strtotime ($date)) +  604800);
echo $date . ' plus 7 days is ' . $date_plus_7;