Having a problem with escapeshellarg in system() command

[noimad1]

Does anyone have experience with the escapeshellarg command within a system() call?

Here is my code:

$path = "/home/mydriectory/";
$path .="$username";

system('mkdir ' .escapeshellarg (path2), $B);

The problem is that code does not create the directory for me. However, if I pass just the $username into the escapeshellarg($username) it will create the directory in the same directory as the script.

I am pretty sure it is the / forward slashes that are causing the problem....would I need to escape the forward slashes for some reason? If so, how would i go about doing that?

Thanks,
Damion

[noimad1]

for anyone that is interested, I got it working with this method:

system('mkdir ' .escapeshellarg ("/home/myaccount/public_html/untar/$username"), $B);