::: expiration year - dropdown box :::

[jduk]

Hi there,

Can any one help me in this drop down year code please.

I have a credit card transaction page, where the user was asked to choose the start and expiration year of his credit card.

Here is the code for the expiration year...

// ######## expiration year ##############

$year = date("Y");
$to = $year + 10;
if ($payment[exp_year] == "") {
$payment[exp_year] = $year;
}
for ($i = $year; $i < $to; $i++) {
$temp = $i;
if ($payment[exp_year] == $temp) {
$years .= "<option value=\"$temp\" selected>$temp";
} else {
$years .= "<option value=\"$temp\">$temp";
	}

}

Can anybody write the code for the start date (10 years) please.

Thanks,

[devinemke]

are you simply trying to display a drop down with the current year plus 10? if so:

$year = date ('Y');
$years = range ($year, $year + 10);

echo '<select name="exp_year">';
foreach ($years as $value) {echo '<option>' . $value;}
echo '</select>';

[jduk]

hi devinemke,

Thanks for the quick reply, the drop down box should disply the years from 1998 to current year. please have a quick look to modify my code plase.

// ######## start year ##############

$year = date("Y");
$to = $year - 10;
if ($payment[start_year] == "") {
$payment[start_year] = $year;
}
for ($i = $year; $i < $to; $i++) {
$temp = $i;
if ($payment[start_year] == $temp) {
$startyears .= "<option value=\"$temp\" selected>$temp";
	} else {
$startyears .= "<option value=\"$temp\">$temp";
	}

} 

---

The name of the select (drop down box) name is "$payment[start_year]"

Thanks,

[devinemke]

$year = date ('Y'); 
$years = range (1998, $year); 

echo '<select name="exp_year">'; 
foreach ($years as $value) {echo '<option>' . $value;} 
echo '</select>';

[jduk]

hi devinemke,

I am sorry, the code you provided will not fit in to my code.
I am calling this function from a php file, the code was as I mentioned above. I am calling the variable in to this HTML .

<select name="start_year">$startyears</select>

So, can you please help me in modifing the function please.

Thnaks,

[Weedpacket]

Originally posted by jduk
hi devinemke,

I am sorry, the code you provided will not fit in to my code.
I am calling this function from a php file, the code was as I mentioned above. I am calling the variable in to this HTML .

<select name="start_year">$startyears</select>

So, can you please help me in modifing the function please.

Thnaks,

Well, let's think this through logically (an ability to do this is very useful when programming).
devinemke wrote

$year = date ('Y'); 
$years = range (1998, $year); 

echo '<select name="exp_year">'; 
foreach ($years as $value) {echo '<option>' . $value;} 
echo '</select>';

And you want something that would fit in

<select name="start_year"><?php echo $startyears?></select>

(or however exactly you want to do it - what you wrote isn't exact).

So you don't need the <select> or </select> tags from devinemke's code, because they're already provided for:

$year = date ('Y'); 
$years = range (1998, $year); 
foreach ($years as $value) {echo '<option>' . $value;} 

And you don't want to echo the <option> entities immediately either, but put them in a string. So let's make a string and put them in there.

$year = date ('Y'); 
$years = range (1998, $year); 
$startyears = '';
foreach ($years as $value) {$startyears.= '<option>' . $value;} 

You don't need to go with ranges or arrays, either. You could just use a for() loop.

$this_year = date ('Y'); 
$startyears = '';
for($year = 1998; $year<=$this_year; $year++) {$startyears.= '<option>' . $year;} 

which is starting to look a lot like the code you started with, only starting from where you wanted and ending where you wanted.

[jduk]

Hi there,

I am attaching the code. Have a quick look at that.