how to reference a variable in seperate PHP file

johnoc

hi guys, really simple question-but i cant seem to find the answer

in 1 php file i have a var called $quizname that is taken in through a textfield (submit button style)...

i can echo that variable within the same php file but..

how to i echo and reference it in a different php file?
in really simple terms 🙂

thanks-John

Kudose

include()

laserlight

It depends.

You might look into [man]include/man.

Or you might be asking how to pass the variables from one page to another other than using a form and the POST method.
The answer would then be by using the GET method, cookies and/or sessions.

johnoc

yes, u see $quizname is referring to an SQL table, so $quizname is taken in through a text field in 1 php file, and in the other php file $quizname is used in the "INSERT into $quizname etc etc" sql command

any ideas?

laserlight

You need to explain the relationship between the 2 PHP files more clearly.

Solving the question shouldnt be much of a problem, the problem here lies in asking the question.

johnoc

i have a variable in 1 doc

i need to reference that variable in a seperate doc

i am using sessions/globals and it is not working
i keep getting "headers already sent out" message for the sessions😕

laserlight

Certain functions, e.g. [man]header/man, [man]setcookie/man, [man]session_start/man with cookies must be called before anything is output to the page.

johnoc

can anyone paste some basic code of 2 sample php files that can demonstrate how i do it?

move3rd

Paste/Post Your code!

tude-marie

if(!isset($_SESSION))
{
session_start();
}

The rest of your code...

Remeber you have to do this on both pages, when you define the variable and when you try to retrieve it!

johnoc

ok i have 1 doc with a php file quiz1.php taking in a variable $quizname through a textfield like so:

<form method="post" action="<?php echo $PHP_SELF?>">
    <p><br>
	  <center><b>Quiz name:</b><br>
      <center><input type="Text" name="quizname" size="50">
      <br><br>
         <center><input type="Submit" name="take" value="Take Quiz" onClick="window.open('quiz2.php','QuizList','width=1000,height=650,left=0')">
    </p>
    </form>

and another php doc (quiz2.php) that contains the code to display the SQL data in a table format, referencing $quizname from quiz1.php

$display = mysql_query("SELECT * FROM $quizname ORDER BY id",$db);

and i get the error

Warning: Supplied argument is not a valid MySQL result resource in c:\apache\htdocs\final\quiz2.php on line 392

and line 392 is

while ($row = mysql_fetch_array($display))