Read filename into a variable

james_cwy

Say for instance I have a few files:
log010104
log020104
log030104

The logs generated were based on the current system date.

How can I read the filename and assign the filename to a variable?

Then after that, I can use this variable and include this in the PHP code to open and read the contents of this file using the general method of opening and reading a file in PHP. That means the user can select to view the files chosen.

Hope you get what I mean.

Hope someone can help me out.

THanks a million
James

laserlight

You could write to some config file, or even the PHP script itself.

Still, by what you described it might be better to store it in some database.

What the user selects would then refer to this database for the associated filename.

james_cwy

My first choice would be using the logfiles.txt.

I just want to keep the files and read the filename into a variable.

Then pass this variable into PHP so as to open and read the file contents.

I am not sure ho to use the database method.

Hope you can provide and example.

THanks
James

laserlight

Well, the simplest method would be to use the query string, say

file.php?log=log010104

then

include $_GET['log'] . '.txt';

to get log010104.txt

james_cwy

Say this is the situation:
log010104
log020104
log030104

Everyday it will generate a log file using the current system date. All files end with the txt extension.

Say today is 040104.

I would like to allow the user to select the files to be viewed for the past three days. But it would be funny to hard code the strings for the filename.
If I do this, that means everyday I would need to modify the PHP code so that the user can view the previous log fies.

Is there a better way to do this?

What I hope to do is: a PHP script will read that directory, get the number of files available, read each filename and put into a variable, generate the list of files that can be viewed through a link. The user needs to just click on the link to view the contents of the file. I was thinking that all these could be done via a while loop but not sure how to start.

Hope you get the picture.

Hope someone can help me out here.

laserlight

The problem here is that there are a number of ways of managing this.

You could use [man]dir/man, [man]opendir/man, [man]readdir/man etc, but a simpler alternative would be to get the script that generates the log files to record the filenames, in a separate textfile, for example.

Then you just open this textfile, say with [man]file/man, and then read from it.

james_cwy

I am actually using a shell script to generate the log files.

I will run this shell script using cron on a daily basis.

I would hope to get the filename and work from there.

Thanks