file exist function

rakennedy75

is there something wrong with this code?

$tempFile = $path.$r['aStock'].".jpg;
	if (file_exists($tempFile)) {
  // this is populated from my database
		$imgFile = $path.$r['aStock'].".jpg";
	} else {
		$imgFile = $path."default.jpg";
	}
echo "<img src='$imgFile'>"

the $tempFile is the path to the file obviously. It is correct, I have tested the path to make sure it is right;

This function seems to print the default.jpg even for the files that do exist;

bubblenut

Well you should be getting parse errors as you've forgotten to close the double quotes on the first line but I'll assume that's a typo. If you were to echo out what's in $imgFile you'd have a better idea of what's going on, it may be that it has unexpected content.
HTH
Bubble

AstroTeg

Originally posted by rakennedy75
is there something wrong with this code?
$tempFile = $path.$r['aStock'].".jpg;
[/B]

Take a look at ".jpg; <-- you need a trailing double quote: ".jpg"; Also note how the colors got screwed up (or is that a bug in the forum?).

What are you using for your PHP editor?

deep

Try this:

$tempFile = $path.$r['aStock'].".jpg"; 
    if (file_exists($tempFile)) { 
        $imgFile = $path.$r['aStock'].".jpg"; 
    } else { 
        $imgFile = $path."default.jpg"; 
    } 
echo '<img src='.$imgFile.'>';

rakennedy75

thanks for the replies....

that was a typo on my part when I typed it in here. It does have the correct quotes on the lines of code. Assuming that the path leads to the correct place. Which I know it does since I echoed out the path as well as an html img tag to see if it would pull the image. The issue has to be the file_exists function. Either I am writing it wrong somewhere or I am forgetting something. Thanks for your help and time.