regexp help, not with the pattern.

michaelkenneth

Hi, I am making a template engine for myself just for practice.

I am using the template syntax for variables like this "{MY_VAR}"

I have found out how to match the template variables with a regular expression.

However, how is it possible for me to get the part of a template variable in between the delimeters( { and } ) into the mixed replacement part?

$tContents = preg_replace("/({[^a-z{}]+})/", MIXED REPLACEMENT, $tContents);

Thanks, Mike

drew010

the pattern
"/{(\w+)}/"
will put whatever is inside {} into the variable $1 (or \1) for use in the replacement string.

michaelkenneth

Originally posted by drew010
the pattern
"/{(\w+)}/"
will put whatever is inside {} into the variable $1 (or \1) for use in the replacement string.

Atleast in my pattern, do you mean that whatever is inside of () will be put into $1?

You said {}.

drew010

well yeah, as the manual states, anything inside () will be assigned a variable starting from 1, but since the () are inside your {} brackets, if you had {HELLO}, the contents of $1 would be "HELLO" by itself, without the {}.
thats what i meant by whatever is inside {} will be put in 1.

michaelkenneth

Awesome, I got it working nicely. 🙂 Thanks.

While I am at it, is there a way to sort of, concate values?

When I do this, the array gets overwritten:

$array = array(
  'element1' => 'cool',
  'element2' => 'dumb');
$array = array(
  'element3' => 'rad';

I know I can easily just create a function to handle this, however I would rather not if there is an easier way to do it directly with php.

drew010

if you have an existing array and you want to add more to it, use array_push
array_push($array, "newvalue");
or the identical function but alternative syntax
$array[] = "newvalue";
which also gives the option of
$array['newkey'] = "newvalue";