Selecting Dropdown list

priya_amb

When I select an iten in the drop down list how do I raise an event to retrieve the details about the selected item from the DB?

webchef

on the same page or on the next page?

PHP is server side.. so you can't display the information based on the selection dynamically without bringing some javascript into play (basically pre-load all possibilites, and use js to display the correct one)...

on a seperate page its easy.. just query the database.

priya_amb

On the same page...

phptrouble

If you want it on the same page you got to set the form action to the same page but also need to set an extra variable to tell the script something is selected.

Try to do where you want the info displayed:

If (do=='1'){
your query
echo it

}
else{}

In your form make a hidden field with the name do and value 1

priya_amb

Yet another problem....

instead of just always echoing the html tags can i not use some document.form,somecontrol stuffs to set values to the html control??

eli03

You can use this

<?
if($_POST['submit']) // variable name of submit button
{
//query

}
?>

priya_amb

say..I need to set values to certain html controls on some condition....

if (isset($_POST['submit']))
{
//without echoing, i need to set some values to certain html controls.
}

How do I do?

zapa

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<HTML>
<HEAD>
<META HTTP-EQUIV="Content-Type" CONTENT="text/html; charset=iso-8859-1">
<TITLE>Untitled Document</TITLE>
</HEAD>

<BODY>
<FORM ACTION="" METHOD="post">
<INPUT NAME="something" TYPE="text" VALUE="Passing me">
<INPUT NAME="submit" TYPE="button" VALUE="submit this form">
</FORM>
<?PHP
if ($_POST['submit']){
print ("You Hit Submit button <BR>\n");
print ($_post['something'] . "was typed in your text box when submiting");
// or do whatever here... pass them into Hidden fields if you want to pass the data on to next form page.
}

?>
</BODY>
</HTML>