Reference a variable via another variable value

everknown

I'm creating code to make creating SQL-enabled forms easier. I define an collection of field objects that define the form.

Example:

$myfields[1]->name = 'firstname'
$myfields[1]->size = '15'
$myfields[1]->maxchar = '15'
$myfields[1]->name = 'firstname'
$myfields[1]->label = 'First Name:'

I have function that prints the HTML for each form based on the field collection

class Table
{
var $fields = array();

function printFieldHTML($n)
{
$v=$this->fields[$n];
$value = ?????????;
printf ("%s ",$v->label);

printf ("<input type='%s' name='%s' size='%s' maxchar='%s' value='%s'><BR>",$v->type,$v->name,$v->size,$v->maxchar,$value );

}

This was working except i need to figure out how to print print the value of the each field as the argument to the VALUE tag of HTML INPUT tag.

I dont know how to use the field[0]->name variable to print the variable that mySQL automatically creates when the user clicks the submit button and the page is reloaded.

I figure I need a function that takes a text value as an argument and prints the value of the variable with this name.

Is this possible with PHP?

LordShryku

variable variables

$var  = "blah";
$blah = "hello";
echo ${$var}; // echos hello

everknown

Well tried doing this in my code and it didn't work. So i tried it using just a simple page and it did work. I'm baffled.

here is my code:

<?php

// start definitions

class Field
{
var $name;
var $label;
var $size;
var $maxchar;
var $type;
var $validationrule;

function Field ($name, $type,$label, $size, $maxchar, $validationrule) {
$this->name = $name;
$this->type = $type;
$this->label=$label;
$this->size=$size;
$this->maxchar=$maxchar;
$this->validationrule=$validationrule;
}
}

class Table
{
var $fields = array();
var $linkedMySQLDB;
var $linkedMySQLTable;

function addField($field)
{
$this->fields[] = $field;
}

function printFieldHTML($n)
{
$v=$this->fields[$n];

echo "<table width='300' border='0'><tr><td width='50%'>";
printf ("%s ",$v->label);
echo "</td><td width='50%'>";
printf ("<input type='%s' name='%s' size='%s' maxchar='%s' value='%s'><BR>",$v->type,$v->name,$v->size,$v->maxchar,${$v->name});
echo "</td> </tr></table>";

}
}

// end definitions

$table2 = new Table();

// ($name, $label, $size, $maxchar, $type, $validationrule)

$table2->linkedMySQLTable = "UserReg";
$table2->addField(new Field('username','text','User name:','10','10','NO NULL'));

?>
<form name="form1" method="post" action="<?php echo $PHP_SELF?>">
<?php
$table2->printfieldHTML(0);
echo "<BR>";
echo "<BR><BR>";

?>
<input type="submit" name="submit" value="Submit">
</form>

</body>
</html>

Originally posted by LordShryku
variable variables
$var  = "blah";
$blah = "hello";
echo ${$var}; // echos hello
[/B]

everknown

Ok the problem was that the FUNCTION does not have access to the globals so i had to use :

$GLOBALS[$v->name] insted of ${$v->name}

Originally posted by everknown
Well tried doing this in my code and it didn't work. So i tried it using just a simple page and it did work. I'm baffled.