PHP and opendir function : mysterious problem

tidou

HI I have a seriouis problem.

I paste you my problem that I have submitted at bugs.php.net

If someone find where could be the problem if it's not a bug in php ...

Thanks in advance

Description:

Hello

The problem is that the script when he scan a sub directory in the drive
cald "D", he failed with the error
"Warning: opendir(d:/Alcatel_save): failed to open dir: Invalid argument
in C:\Inetpub\wwwroot\lister.php on line 8
".

This problem only occure when the script try to open with the "opendir"
function a subdirectory in the drive "D" but with drive C: it works
perfectly.

The script has no problem to open dir in the drive d: but this error
only occure when he try to open a SUBDIRECTORY !!!

The permission are the same than the other directory in c: and d:
driver.

Reproduce code:

<?php

$tab_deja_vu = array();
recurse_dir('d:', $tab_deja_vu);

function recurse_dir($rep, $tab_deja_vu)
{
$open = opendir($rep);

while($sous_rep = readdir($open))
{
if(is_dir($rep . '/' . $sous_rep) && $sous_rep != '.' && $sous_rep
!= '..')
{
if(!array_key_exists($rep . '/' . $sous_rep, $tab_deja_vu))
{
echo '<option
value="'.$rep.'/'.$sous_rep.'">'.$rep.'/'.$sous_rep.'';
$tab_deja_vu[] = $rep . '/' . $sous_rep;
recurse_dir($rep . '/' . $sous_rep, $tab_deja_vu);
}
}
}
closedir($open);
}
?>

Expected result:

The script should save in the array "$tab_deja_vu" the entire directory
and sub directory etc of a given directory in parameter.

Actual result:

d:/Alcatel_save
Warning: opendir(d:/Alcatel_save): failed to open dir: Invalid argument
in C:\Inetpub\wwwroot\lister.php on line 8

Warning: readdir(): supplied argument is not a valid Directory resource
in C:\Inetpub\wwwroot\lister.php on line 10

Warning: closedir(): supplied argument is not a valid Directory resource
in C:\Inetpub\wwwroot\lister.php on line 22
d:/Cerpass_save
Warning: opendir(d:/Cerpass_save): failed to open dir: Invalid argument
in C:\Inetpub\wwwroot\lister.php on line 8

Warning: readdir(): supplied argument is not a valid Directory resource
in C:\Inetpub\wwwroot\lister.php on line 10

Warning: closedir(): supplied argument is not a valid Directory resource
in C:\Inetpub\wwwroot\lister.php on line 22
d:/Copilote_save

etc ... the error "supplied argument is not a valid Directory resource
in C:\Inetpub\wwwroot\lister.php on " appears every time the opendir
function try to open a sub directory on drive d:

tidou

up
🙂

TheDefender

Please don't bump your post. It isn't going to help you get your question answered any faster, and in fact, it just serves to annoy the regulars anyhow. (And you really don't want to get on their bad side if you want/need their help.)

I am not 100% sure, but I think the opendir looks for the backslash on Windows machines when dealing with the Windows file structure. Instead of using the path as d:/whatever, change your code to look in d:\whatever. Try that first, and post back the results.

tidou

I have try with / or \ but the same error occure in some case that I have said in my previous post.

Nobody has answered my byg at bugs.php.net so I wait that the phpteam make a patch ... :bemused:

TheDefender

Well, you didn't say anything about the results with the slash going in either direction in your previous post, so that's why I mentioned it to begin with.

Let's look at the beginning of your function:

<?php 

$tab_deja_vu = array(); 
recurse_dir('d:', $tab_deja_vu); 

function recurse_dir($rep, $tab_deja_vu) 
{ 
$open = opendir($rep);

Where is $rep being defined? The error begins with the $open = opendir($rep); call, so let's start there. I don't see in your script where it is defined.

Incidentally, 99.99% of all of the problems ever posted here exist between the keyboard and the chair (ie, they are a coding problem by the user), and are not bugs requiring patches, so have patience while we work through it.

tidou

no it's not a coding problem.

If I do

$open = opendir('d:\toto');

it failed with error "Warning: opendir(d:/Alcatel_save): failed to open dir: Invalid argument ".

But if I do $open = opendir('c:\toto'); it works.

The problem only exist when I try to open a directory in drive D:

This code work also too

$open = opendir('d:');

So my function works fine, the problem is in PHP with IIS I think.

Nobody reply to my post at bugs.php.net ... I wait for a possible patch 🙁

TheDefender

My question to you is this:

$open = opendir('d:\toto'); 

it failed with error "Warning: opendir(d:/Alcatel_save): failed to open dir: Invalid argument ".

If you are trying to open d:\toto, then why does your error say d:/Alcatel_save?

And again I ask you: Where is the $rep variable being defined in your code?

TheDefender

The reason I ask is because I use Win2000 on my intranet server, and have no problems opening any directories on it. Is the D Drive a local drive, or is it a network drive. (Just out of curiosity).

tidou

it's a local hard drive