PHP and CSS; Two pages, two views but one stylesheet

[Edward_1980]

Hi everyone,

I'm facing a problem and I don't know how to solve it (nor if it can be solved). I want my website to have different colours depending on the directory of the file. For example:
http://www.bruheim.net/nieuws/ becomes yellow fonts.
http://www.bruheim.net/reizen/ becomes red fonts.

My stylesheet is called 'normal.css.php'. Some of the code:
<?php
header("Content-type: text/css");
// der richtige MIME-Typ:
// include ("kleurenkiezer.php");

switch($mycolor) {
case "Nieuws" : { $hardcolor = "#FFFF00"; $softcolor = "#FEFF91";} break;
case "Reizen" : { $hardcolor = "#0000FF"; $softcolor = "#9194FF";} break;
case "css" : { $hardcolor = "#00FF00"; $softcolor = "#91FF91";} break;
case "bruheim" : { $hardcolor = "#FF0000"; $softcolor = "#FF9191";} break;
default:{
$hardcolor = "#9933FF";
$softcolor = "#9194FF";
;}
}
?>

The code from 'kleurenkiezer.php ' is this:

<?php
// Een arry bc_label vullen:
$bc_label = array(
"nieuws" => "Nieuws",
"reizen" => "Reizen",
"css" => "css",
"bruheim" => "bruheim"
);
$myhost = $SERVER['HTTP_HOST']; // What is the current host?
$mysite = $SERVER['PHP_SELF']; // What comes behind that in the url?
//echo ("Mijn site: $mysite <BR>");
$str = substr(dirname($mysite), 1); // Which sub-directories am I working in?
//echo ("String: $str <BR>");
$arr = split('/', $str); // Splitting string by /
$num = count($arr); // How many sub-directories?
//echo ("delen: $num <BR>");
$val = $arr[2]; // Take the first array and call it $val (was 0)
//echo ("$val"); // What is $val?
$mycolor = $bc_label[$val]; // Take the code from above.
?>

The problem:
'kleurenkiezer.php' works fine, but doesn't work correct when it is included in the Stylesheet. In that case the res
E16
ult is always 'css'. I don't want a second stylesheet, as that gives you much work if you want something to alter later. But is there an other solution for this problem?

[yelvington]

You are using a PHP-generated external stylesheet. That stylesheet needs to "know" the directory structure of the page that refers to it.

In your example, the stylesheet is discovering its own directory path, not the path of the page containing the HTML.

The page containing the HTML -- not the stylesheet -- needs to include('kleurenkiezer.php'), then pass the computed value to the stylesheet like this:

<LINK href="normal.css.php?mycolor=<? echo $mycolor ?>" rel="stylesheet" type="text/css">

The stylesheet then can refer to $_GET['mycolor'] and apply the appropriate value, as you have done in your example.

Be careful with case sensitivity on directory names.

[Edward_1980]

Thank you yelvington! The script is working now correctly and I think I can understand the point. Things like require() and include() really incorporate the pages they refer to, where as the <LINK>-thing refers to an external stylesheet which stays for ever like that: used but outside.