Hi!

Could anyone help me to add some PHP to the following Javascript:

http://javascript.internet.com/forms/form-swapper-2.html ?

What I am trying to build is a system where the SELECT from the left should be loaded from a mySQL table and then, after choosing 2 or 3 items, be able to obtain a PHP array with the chosen items on the right...

I will apreciate your kind help!
Thank you very much

    here the BASIC idea

    // assuming already connected to db
$result = mysql_query('SELECT * FROM table');

echo '
<form action="' . $_SERVER['PHP_SELF'] . '" method="POST">
<select name="list[]" multiple>
';

while ($row = mysql_fetch_assoc ($result))
{
	echo '<option>' . $row['field'] . "\n";
}

echo '
</select><br>
<input type="submit" name="submit" value="submit">
</form>
';

if (isset($_POST['submit']))
{
	if (isset($_POST['list']))
	{
		echo 'you selected:<br><br>';
		foreach ($_POST['list'] as $value)
		{
			echo stripslashes($value) . '<br>';
		}
	}
	else {echo 'you did not select anything';}
}

      Thank you so much!!!

      This is a very good start...

      What is difficult for me in this case is to make the Javascript code to interact with PHP to pass the 2nd SELECT contents...

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