Listing Array From Database Horizonal Not Vertical

ethanlee1

Basically, I am trying to have fetched database images and info displayed across rows of a table instead of straight down one column of a row the way the code is now. I've tried using an <ul>, but that didn't work. I think it has something to do with the way the print function works, but I can't seem to figure it out. I also thought it had something to do with the $list function, but I don't know what to replace it with. I believe that $x is the row and $k is the column even though it doesn't show $k.

Please help....Thank you.

<table width="700" border="0" cellspacing="0" cellpadding="0" align="center">
<?php
$x = 0;

		while($list = mysql_fetch_array($result[result])){
	?>

<?php $array = $list[pPhoto] ? $db->scalePhoto($list[pPhotoWidth], $list[pPhotoHeight]) : array("width" => "75", "height" => "75"); ?>

<tr>
<td width="197" valign="top"><a href="<?php print $PHP_SELF; ?>?m=product_detail&p=<?php print $list[pID]; ?>"><img src="<?php print $db->productIMGurl; ?>/<?php $list[pPhoto] ? print $list[pPhoto] : print "na.gif"; ?>" width=<?php print $array[width]; ?> height=<?php print $array[height]; ?> border=0></a>
</td>

<?php
$x++;

		}
	?>

</table>

elementaluk

...ok

i'll just write a small for loop to show you how this may be done:

//ok you have an array somewhere called $db ok, dont argue
$per_row=5;
for($i=0; $i < count($db); $i++)
{
     print("a table that has <tr>&<td>'s...cant be bothered");
     if($i == $per_row) //have we done another 5 yet?
     {
          print("</tr><tr>");
          $per_row = $per_row+5; //add 5
     }
}

ok, if that doesn't work dont blame me, i'm pretty tired and really couldn't be bothered.