[Resolved] variable variables

[knucklehead]

hello!
i red about variable variables in php manual but the thing won't work and it's driving me crazy so please help!
i have this code:

for ($i=1; $i <= 10; $i++) {
echo "<input name='thumbnail_$i' type='text' class='input' value='XXX'><br>";
}

the problem is that i have 10 thumbnails in table and i have to display values from table in 'value' option. so how to join variable $row['thumbnail'] and another variable (in my case $i)?
thanks!

[laserlight]

the problem is that i have 10 thumbnails in table and i have to display values from table in 'value' option.

Could you explain a bit more?
I dont understand the problem.

[lazzerous]

$get_thumbs = mysql_query("select thumbnail from thumbnails limit 1,10");

$i="0";
while ($row=mysql_fetch_array($get_thumbs))
    {
    echo "<input name='thumbnail_$i' type='text' class='input' value='$row[thumbnail]'><br>";
    $i++;
    }

is this what you were looking for?

[knucklehead]

sorry, i'll try to be more specific:

first of all i have a table with these columns:

• file_1
• thumbnail_1
• title_1
• file_2
• thumbnail_2
• title_2
• file_3
• thumbnail_3
• title_3
...
• file_10
• thumbnail_10
• title_10

so on my page i created input fields with FOR loop:

for ($i=1; $i <= 10; $i++) {
echo "THUMBNAIL $i: ";
echo "<input name='thumbnail_$i' type='text'><br>";
echo "FILE $i: ";
echo "<input name='file_$i' type='text'><br>";
echo "TITLE $i: ";
echo "<input name='title_$i' type='text'><br>";
}
echo "<input name='submit' type='submit' value='[SUBMIT]'>";

and that part works ok.
but when i want to use edit mode i have to pull out values of the fields from a table. i want to do that with FOR loop again. so it would be something like this:

for ($i=1; $i <= 10; $i++) {
echo "THUMBNAIL $i: ";
echo "<input name='thumbnail_$i' type='text' value='$row[\'thumbnail\']'><br>";
echo "FILE $i: ";
echo "<input name='file_$i' type='text' value='$row[\'name\']'><br>";
echo "TITLE $i: ";
echo "<input name='title_$i' type='text' value='$row[\'title\']'><br>";
}
echo "<input name='submit' type='submit' value='[EDIT]'>";

ok, that will obviously not work because $row[thumbnail], $row[name] and $row[title] don't exist. so i would like to join $i to that $row[...] variable so it would produce $row[thumbnail_1], $row[thumbnail_2], $row[thumbnail_3] etc. and same with the $row[name_1], $row[name_2]... and $row[title_1], $row[title_2]...

so, that's it i think... hope that you will now understand my problem...

thanks in advance!

[Gestahr]

I think I understand what you're trying to do, however, I may be wrong, so please forgive me if my response isn't germaine to your question.

Anyhoo, I think I've done what you're doing, and I generally do it through concatenation. IE,

for ($i=1; $i <= 10; $i++) {
$name = "name" . "_" . $i;

echo "<input name='file_$i' type='text' value='$row['$name']'><br>";
}

I think that should work.

[lazzerous]

${"row[thumbnail_$i]"}

[knucklehead]

Originally posted by lazzerous
${"row[thumbnail_$i]"}

that's the solution! thanks for that 🙂