array_key_exists

[corruption]

it was suggested to me that i use array_key_exists to check if a user was logged in instead of $_session...
so here's the example that i found on php.net

<?php
$search_array = array("first" => 1, "second" => 4);
if (array_key_exists("first", $search_array)) {
   echo "The 'first' element is in the array";
}
?> 

I'm not entirely sure of the structure here but here's what i came up with for my own code.

<?
$search_array = array("fname" => 1, "lname" => 2, "number" => 3, "id" => 5);
if (array_key_exists("fname", $search_array)) {
   echo "The 'first' element is in the array";
}
?>

[drawmack]

If you're searching in the session array then use the session array

<?php
if(array_key_exists('key',$_SESSION)) {
  //this is where the code for success goes
} else {
  //this is where the code for failure goes
}
?>

What you have above will always be true, because you're creating the array with the desired key and then checking to see if the desired key exists. That's kind of like saying Am I wearing what I just put on.

[corruption]

<?php
// check the session
session_start());

if(array_key_exists('fname',$_SESSION)) {
  //this is where the code for success goes
  echo 'success we should forward you to the brothers page';
} else {
  //this is where the code for failure goes
  echo 'You suck you are not a brother';
}
?>

this code displays a blank page.