what is the uploaded image path?

[scorpioy]

I created a webpage that has a form for the user to input some strings and upload images. When the user uploads an image, I move it to a folder, say, 'C:/user/image/image_name.jpg' and store this path in the mysql. I created a link that the user can click to see the uploaded image. But this only works on my own machine. If I test it on the internet, the path is still ' C:/user/image/image_name.jpg ', which will cause the client machine to look for its own C driver. So does any one know what path should I store would be correctly allows client machine users to see uploaded images?

Another problem I found is when I test my webpage on some machines, the alignment of lines in the form is not the same as what I see on my own machines. (I use '&nbsp' to create a blank space). How do solve this problem?

Thanks.

[sid]

can you post a part of the code you are using? what you are storing is the source path of the file that was uploaded - so the image thats being linked and displayed actually is the one on your local machnine, not the one on your server!

first off, check out this, to understand the use of the global $_FILES array: http://us4.php.net/features.file-upload

then - as i said - post some code and we'll help.

sid

[tommynanda]

create a new php file: showimg.php
use fpassthru() function with proper headers for images in this file

in your HTML use
<img src="showimg.php">

example for showimg.php

<?php

// open the file in a binary mode
$filename = "apache.gif"; // this can be your link obtained from MySQL db
$fp = fopen($filename, 'rb');

// send the right headers
header("Content-Type: image/gif"); //This is for GIF check extension and change accordingly
header("Content-Length: " . filesize($filename));

// dump the picture and stop the script
fpassthru($fp);
exit;

?>

Good Luck
TommYNandA

[scorpioy]

Here is my code:

                                             if (!empty($_FILES['userfile']['tmp_name'])) 
		{				
			$fs = filesize($_FILES['userfile']['tmp_name']);


			$HTTP_POST_FILES['userfile']['name'];

			if($fs>200000)  //200KB  
			{
				$error= "You picture size is great than 200KB. Upload is canceled.";
			}
			else
			{
				if(!is_dir("C:/user/image/$member"))			//dir does not exist
					mkdir ("C:/user/image/$member", 0700);

				if(!move_uploaded_file($_FILES['userfile']['tmp_name'], "C:/user/image/$member/$item_name.jpg")) 
					echo  "File failed to move";				
				else 
				{
					//$userfile_type = $HTTP_POST_FILES['userfile']['type'];						
					//echo "type >> $userfile_type";


					$sql = "insert into furniture values ('$member', '$item_name', '$quality', '$price', '$other', CURDATE(), 'C:/user/image/$member/$item_name.jpg')";										

					if (! @mysql_query($sql)) 
						echo  "<p>Error in adding: mysql_error().  </p>"; 	
				}
			}			


		}

I just began to doubt that if this: 'mkdir ("C:/user/image/$member", 0700);' is the cause of the problem. Should I set it as 0777?

When I test the webpage on a client machine, the image that is supposed to be shown only has a cross on a rectangle, and I go back my own machine, I saw the image has been successfully uploaded and moved to the desinated directory. So I thought the problem came from the path, but I'm not 100% sure.

Thanks.

[tommynanda]

If you are using Windows mode doesnt effect... It is ignored by PHP on Win32.. so it can be 700 or watever until u are on Windows

[scorpioy]

Originally posted by tommynanda

example for showimg.php

<?php

// open the file in a binary mode
$filename = "apache.gif"; // this can be your link obtained from MySQL db
$fp = fopen($filename, 'rb');

// send the right headers
header("Content-Type: image/gif"); //This is for GIF check extension and change accordingly
header("Content-Length: " . filesize($filename));

// dump the picture and stop the script
fpassthru($fp);
exit;

?>

TommYNandA [/B]

I tried the way shown above, but the page displays messy and unreadable strings. It seems to displays binary file. The image I uploaded is jpg type. Then in the code I just change the Content-type to image/jpg, but It does not work.

Anywhere else I should change my code?

Thanks.

[tommynanda]

Works fine with JPG too, let me explain a little better

Create 2 files imagestream.html, getimage.php
include the following codes accordingly

imagestream.html

<body>
<img src="getimage.php">
</body>

now getimage.php

<?php
$filename = "C:/user/image/image_name.jpg";
$fp = fopen($filename, 'rb');
header("Content-Type: image/jpg");
header("Content-Length: " . filesize($filename));
fpassthru($fp);
exit;
?>

now in your browser, type
http://localhost/wateverfolder/imagestream.html

This should work

Good Luck
TommYNandA

[scorpioy]

Thanks. It works now.

instead of using:
<body>
<img src="getimage.php">
</body>

actually I have to use <img src="getimage.php?path=$filePath"> in order to pass the image path to getimage.php, which is on C:/user/image/image_name.jpg. The user can know where exactly images are stored on the server by right clicking the image and choose the property.

Is there any way I can hide the path? I want to prevent the user to know this detail.

Thank you aagin.

[tommynanda]

use
<img src="getimage.php?path=$fileName&folder=$foldername&user=$username">

and in getimage.php

$filepath = "C:/$user/$folder/$fileName";
$fp = fopen($filepath, 'rb');
...
.
.
.

or

Since you said u have path stored in MySQL database just pass ID
like
<img src="getimage.php?id=someid">

in getimage.php use MySQL query
SELECT file_path FROM tablename WHERE file_id=$id

the result should give you filepath and you can continue with that

TommYNandA