linking images

[dreams4000]

Hi all,

Is there any way in php to link to dynamic images but if the image doesnt exist, then link to another? ie...

 if (image one exists) {
Display one img src url
} else {
Display some other image src url
}

The image I am looking for is at an external url. I just want to have it show the active image if it is there, if not I want it to show some other image that says no info available. any ideas? thanks!

[lazzerous]

you were very close

if (file_exists($image_one))
    {
    echo "<img src='$image_one_src'>\n";
    }
else
    {
    echo "<img src='$image_two_src'>\n";
    }

[dreams4000]

Is there a way to put the url in the $image_one variable? I tried putting the url as a variable and using that, also tried putting the url directly into it.. neither worked on that.. $image_one isnt on the local, it is at a remote location.. so I need to say.. if img src "http:// ...someimage.gif"> exists then show it, otherwise show the second image.

[silent]

If the file is on a server that is TOTALLY remote to you, then
the best way I can think of is to open the file over the URL, and
if fopen gets an error, then it doesn't exist.
Something like this :

<?php
  if(!($fp = @fopen('http://someimage','r'))) {
    echo '<img src="" alt="Some other image">';
  } else {
     echo '<img src="someimage.jpg">';
  }
  fclose($fp);
?>

Hope it helps

[dreams4000]

I made a few adjustments, but it worked right. Thanks much! Folks on these forums are wonderful for helping people!

[silent]

If that worked for you, please mark the thread resolved!

[dreams4000]

I tried by changing the topic at the top, but that doesnt seem to do it. How else is that done? Thanks!

[silent]

Click http://www.phpbuilder.com/board/showthread.php?s=&postid=10527254#post10527254&is_resolved=1

(but the link itself is at the bottom of the page)