preg_replace problem can someone help

[johnskywalker99]

Hello
I'm using preg_replace to parse a bulletin board type tag [img] into a <img scr=""> tag. The format of the path to the image is something like 0200_0000_name.ext where the "02" changes depending on what directory the image is stored in. So I basically want 0200_0000_name.ext to become 02/02_00_0000_name.ext once parsed. I tried the following:

$pattern = "/[img(left|right)?](([^<> \n]+?).(gif|jpg|jpeg|png))[\/img]/i";

$ImagePath = "\2";
$dir = explode("/", $ImagePath);
$ContentFolder = $dir[0];

$replacement = '<img src="content/images/$ContentFolder/\2" border="1" align="\1" alt="" hspace="10" vspace="b">';
$FormText = preg_replace($pattern, $replacement, $FormText);

But in only prints the var name "content/images/$ContentFolder/" not the value of $ContentFolder could some plese tell me how to achieve the correct result.

Many thanks in advance for any help given.

John

[Weedpacket]

Try using double quotes instead of single quotes and your variables will be interpolated (don't forget to escape the double quotes already there). Or use string catenation instead of interpolation.

[johnskywalker99]

Thats great the variable now prints as a value but the explode("", $2); doesn't work it only returns one value $dir[0] which is just the data that was passed to it 02_00_0000_name.txt. Do you know how I could explode the name into an array on the "" or another way in which this could be achieved?

Many thanks

John

[johnskywalker99]

not what I wanted but I just went the long way around and changed the filename structure.

cheers