[Resolved] Undesired results in getting variable's value

[jawa]

I am concatenating a for loop counter to a string. When I echo it, I get the variable as a string as opposed to the variable's actual value. For instance,

$store1 = 'a';
$store2 = 'b';

for ($i=1;$i<=2;$i++) {
     	$store_number = "\$store" . "$i";
	echo($store_number); 
}

gives me $store1$store2

I would like to see: ab

In JavaScript, I would use an eval, but the eval() function gives me all sorts of funky errors in PHP.

Thanks for the help...
-J

[tommynanda]

why not use arrays, like this:

$store[1] = 'a'; 
$store[2]= 'b'; 

for ($i=1;$i<=2;$i++) { 
         $store_number = $store[$i]; 
    echo($store_number);  

}

or... if you want to use your way... you may want to think about variable variables

<?
$store1 = 'a';
$store2 = 'b';

for ($i=1;$i<=2;$i++) {
         $store_number = "store".$i;
    echo(${$store_number});
}
?>

This is an interesting concept in PHP, check manual for more abt variable variables....

Have Fun!
TommYNandA

[jawa]

Never even thought to use arrays, and I've been trying to get the variable variables to work for several hours.

I incorporated the array logic, and voila! Thanks tommynanda...

-J

[tommynanda]

YW, arrays are good... variable variables is an interesting concept... might come handy sometimes... keep an eye on it 😉

Have Fun!
TommYNandA