Using hidden input w/ image assigned VARS

slash5

Hi,

Please bare with me on this cos I've found it difficult to explain.

I've been making a four step html form for booking a performance (i.e. select a performance, fill out no. of tickets etc, preview, thank you page).
I've written the script so that each of the four pages is echoed in their own function and uses a hidden field in each page to call the next function :

//performer images
$i1 == "<img src=\"image1.jpg\" width=\"84\" height=\"136\">";
$i2 == "<img src=\"image2.jpg\" width=\"84\" height=\"136\">";

//performer's names
$n1 == "whoever";
$n1 == "someone";

if ($page1 == "book") {
$performer_image == $i1;
$performer_name == $n1;
function2();
}
elseif ($page2 == "book") {
$performer_image == $i2;
$performer_name == $n2;
function2();
}
... and then use hidden input and global to pass the variables $performer_image and $performer_name on to each of the other pages.

Basically, each performance has its own image and, depending on what performance is chosen, I want that image to appear on each booking page. As if each performance has its own booking section of the website. That's were my problem is. As the performances will change every month, I thought it would be easier if I made a variable for each image and used hidden input and global to pass it on to each page.

This works for text:

but when I use a hidden field to attempt to pass on my image it's not working:

Is there an easier way to do this??
It's frustrating because it's working for text and not my image tag.

Hope it makes sense.
Any help would be appreciated,
Chris

Shrike

To be frank, use a database.

The reason it doesn't work is that your using the comparison operator (==) rather than the assignment operator (=) when setting variables.

slash5

Sorry, I copied it out wrong in my first post. I am actually using (=) not (==).

Everything else in the script works fine it's just when I set a variable with the img src tag and then try to pass it using a hidden field that isn't working.

Thanx anyway

jordy

A easy way to post items to the next form is using the foreach and the $_POST array..

every form gets a step variable:

<input type=hidden name=formstep value=1>.. next <input type=hidden name=formstep value=2> etc etc etc.

now you can try this after submission:

$currentpost = ($POST[formstep]) ? $POST[formstep] : 0;

switch ($currentpost) {
case "1" :
// $error = test routine
break;
case "2" :
// $error = test routine
break;
default :
// $error = test routine
break;
}

$hidden = "";
foreach ($_POST as $key => $val) {
if ($key == "formstep") continue;
// other vals that are not needed can be dodged in the
// same way as above
$hidden .= "<input type=hidden name=$key value=$val>\n";
}

if ($error) {
// print the current form with the error message
// and $hidden var
}
else {
// print the next form
// and $hidden var
}