Move files from 1 server to another

macastor

Hello everyone,
I'm fairly new to PHP, and I was wondering if there is an easy way to move a csv file from one server to another. And will there be any file permissions that need to be set before transferring this file from one sever to another. Oh, and ftp server is not set up on destination server so don't think I can use ftp.

Thanks!

jordy

There are several ways to do this if the CSV file is within the scope of the webserver...

lets assume the file's url is:
http://server1.example.com/my.csv

on server 2 you can:
<?
$handle = fopen ("http://server1.example.com/my.csv", "r");
$result = fread($handle,8192);
echo $result;
?>

more info:
- http://nl.php.net/manual/nl/function.fopen.php

macastor

Thanks jordy,
Now do I need Apache Services running on both server's???

jordy

macastor,

no its webserver independant. The request is made by php itself. So you can access every http and ftp doc with this function... i use it myself very often to rip certain information from different websites..

Yours,

Jordy

macastor

jordy,
I must be doing something wrong then, cause all I'm doing is a simple open & close and I keep getting this damm error.

Warning: fopen(http://srvrname/CampLoad/musa0705.csv): failed to open stream: HTTP request failed! HTTP/1.1 404 Not Found in C:\Program Files\Apache Group\Apache2\htdocs\MPI\testinc.php on line 7

Warning: fclose(): supplied argument is not a valid stream resource in C:\Program Files\Apache Group\Apache2\htdocs\MPI\testinc.php on line 8

Here's my code:
<?php

$fp = fopen("http://srvname/CampLoad/musa0705.csv", "r");
fclose($fp);

<?php

Hope you can help.

jordy

the server gets a 404 not found error.. so are you sure the link you are trying to open is valid?! if you have shell access to the server you might want to try to open the link with lynx or wget to validate the link..

macastor

jordy,
Not sure how exactly to do this.... You mind explaining. Thanks!

jordy

in this example you try to open:

http://srvname/CampLoad/musa0705.csv

The error is:

Warning: fopen(http://srvrname/CampLoad/musa0705.csv): failed to open stream: HTTP request failed! HTTP/1.1 404 Not Found in C:\Program Files\Apache Group\Apache2\htdocs\MPI\testinc.php on line 7

what the webserver tries to tell you is that he connected to the given link and got the following error from the webserver: HTTP request failed! HTTP/1.1 404 Not Found, wich is a normal http error for a file that is not found.

So you can try to copy the link from the php script and open it in Internet Explorer. If the link is invalid there as well than you should check the url. If the link opens normally then its possible that the servername in the link is not recognized by the webserver. (eg. if you are really using srvrname wich is a local server and the webserver is not its normal he can not connect to the location).

If the server is not maintained by you then you can try to telnet into the webserver. This option is not always possible as some service providers block this..

in windows:

start button > run > type: telnet webservername > enter
the webservername is the name of the webserver. Usually the same as www.yourdomain.com

log in using your username and password provided by the service provider. If logged in type: wget http://srvrname/CampLoad/musa0705.csv.

if the command wget is not found then you can try it with lynx: lynx http://srvrname/CampLoad/musa0705.csv.

if one of the two programs give you the same error (404 not found) then it means that the link is valid (you can open it from your own computer) but the server cannot find it. If this is the problem you could contact the server maintainer.

The problem is not in the php code given by you...