Baisc PHP problem.

eliran

First of all, I'm glad to be here. This looks like a proffesional PHP Forum. I apologize for English mistakes before hand. Hebrew is my mother's language.

Ok. now my Basic question.
I have 2 PHP files on a server called 1.php & 2.php

1.php :

</body>
</html>

and 2.php

<?php

echo "Welcome to our Web site, {$GET['firstname']} {$GET['lastname']}!!";
?>

but when i open 1.php in a browser, i get an empty screen ! i dont see why ?

but if i open http://127.0.0.1/2.php?firstname=test then i get the response i'm expecting.

Any ideas ?

Thanks in advance,

          Eliran.

eriksmoen

Try this:

1.php :

<html>
<head>
</head>
<body>
<a href="2.php?firstname=Kevin&lastname=Yank">Kevin Yank</a>

</body>
</html>

and 2.php

<?php

echo "Welcome to our Web site, ".$GET['firstname']." ".$GET['lastname']."!!";
?>

hope that helps

eliran

Thanks for the quick response.
It still does not work. I'm expecting 2.php to display my name, which is passed from 1.php, but it does not work. why ?

Tnx again.

dalecosp

OK, back to square one ... what is the real problem?

In your first post, you said that "1.php" did not display anything.

In your next post, you said that "2.php does not display what I expect", which makes me assume that "1.php" does do as you expect?

Knowing the real problem helps with the real answer 😉

In simply thinking about the issue, a few general thoughts:

a. "1.php" is pure HTML. Does it work as you expect if it's named "1.html" instead of "1.php" ?

b. Take a look at the "Debugging 101" thread (IIRC, it's a "sticky" post in the "Echo Lounge" forum). Among the many ideas there that might help: using [man]print_r/man or [man]var_dump/man to inspect the contents of superglobal arrays, e.g. :


2:php

<?php

// debug only, remove these lines for production...

print_r($_GET);
exit();

// the rest of our script

 echo "Welcome to our Web site, {$_GET['firstname']} {$_GET['lastname']}!!";
?>

c. Is anything appearing in your server logs? In a production environment, PHP generally prints error messages to the log instead of the browser ...

HTH,

eliran

Ok. I have this file , 1.php, which calls 2.php, with parameters.
I expect file 1.php to call 2.php with parameters, and i expect 2.php to print these out.
file 1.php reads
<html>
<head>
</head>
<body>
<a href="2.php?firstname=Print&lastname=This"></a>

</body>
</html>

and file 2.php reads

<?php
print_r($GET);
exit();
echo "Welcome to our Web site, ".$GET['firstname']." ".$_GET['lastname']."!!";
?>

I'm SURE i have a stupid mistake here, but being a complete newbie to PHP, i cant find it my self.

Your first suggestion made 1.php print out the string, but thats not what i wanted. I want 2.php to get the parameters, and then print them out to the screen.

Hope thats clear now. Tnx !

dalecosp

Well, the link doesn't look right, also. Anyway, try this, and if it still doesn't work, take the afternoon off, I guess.

//1.php or 1.html:   <whatever>

<html>
<body>
<a href="2.php?firstname=foo&lastname=bar">Click here!</a>
</body>
</html>

2.php:

<?php

echo "Welcome to the site, ".$_GET['firstname']."  ".$_GET['lastname'];

?>

Ceril

Originally posted by eliran
Ok. I have this file , 1.php, which calls 2.php, with parameters.
I expect file 1.php to call 2.php with parameters, and i expect 2.php to print these out.
file 1.php reads
<html>
<head>
</head>
<body>
<a href="2.php?firstname=Print&lastname=This"></a>

</body>
</html>

and file 2.php reads

<?php
print_r($GET);
exit();
echo "Welcome to our Web site, ".$GET['firstname']." ".$_GET['lastname']."!!";
?>

I'm SURE i have a stupid mistake here, but being a complete newbie to PHP, i cant find it my self.

Your first suggestion made 1.php print out the string, but thats not what i wanted. I want 2.php to get the parameters, and then print them out to the screen.

Hope thats clear now. Tnx !

cough
What you have here is a little confusion.

1.php:

</body>

</html>

Now the above is just HTML, no php and you have missed that a link <a tag is a just that a hyperlink to another document.
And you have not closed it correctly:
<a href="2.php?firstname=Kevin&lastname=Yank">This is Kevin Yank</a>

the </a> closes the a tag. why your 1.php comes out blank at first is because the link that is never closed and the document does not contain anything, and thus 1.php comes back blank, as it should.

Now when it is closed and a linkname (This is Kevin Yank) will be displayed on the page.
Once you click this hyperlink you are however taken to 2.php with the GET variables firstname and lastname = Kevin and Yank

If you wanted 1.php to automagicly transfer the one opening the page to 2.php and execute it. your 1.php should look like this:

1.php:

<?PHP
header("location: 2.php?firstname=Kevin&lastname=Yank");
die();
?>

Nothing else, but this redirects the browser to 2.php with the values you wanted.

So as I said above, your a bit confused as to what does what.
Suggest you start with learning the basics of html.

eliran

Thank you VERY much for your kind (!) help.
I figured it out later on, and i have it working now.
The problem is i dont know HTML nor PHP, and i'm trying to learn both, at the same time, while bashing my head against the computer.

Thanks again !

Originally posted by Ceril
cough
What you have here is a little confusion.

1.php:

<html>
<head>
</head>
<body>
<a href="2.php?firstname=Kevin&lastname=Yank">

</body>

</html>

Now the above is just HTML, no php and you have missed that a link <a tag is a just that a hyperlink to another document.
And you have not closed it correctly:
<a href="2.php?firstname=Kevin&lastname=Yank">This is Kevin Yank</a>

the </a> closes the a tag. why your 1.php comes out blank at first is because the link that is never closed and the document does not contain anything, and thus 1.php comes back blank, as it should.

Now when it is closed and a linkname (This is Kevin Yank) will be displayed on the page.
Once you click this hyperlink you are however taken to 2.php with the GET variables firstname and lastname = Kevin and Yank

If you wanted 1.php to automagicly transfer the one opening the page to 2.php and execute it. your 1.php should look like this:

1.php:

<?PHP
header("location: 2.php?firstname=Kevin&lastname=Yank");
die();
?>

-----------
Nothing else, but this redirects the browser to 2.php with the values you wanted.

So as I said above, your a bit confused as to what does what.
Suggest you start with learning the basics of html.