Check to see whether a variable has a certain value

[dr0n3]

The following names are acceptable values for the variable $member.

Allison
David
Brian
Eric
Ben
Mark
Mike

How do I check whether $member equals one of the above values and not something else?

I can do the following, but it is very tedious.

$error=FALSE;

if($name!="Allison")
    {
    $error=TRUE;
    }

if($name!="David")
    {
    $error=TRUE;
    }

if($name!="Brian")
    {
    $error=TRUE;
    }

etc

How can I put it into an array or shorten it another way?

[bubblenut]

Lots of different ways.
With "&&"
[edit]Ooops! bad logic 😊[/edit]

if($name!="Allison" && $name!="David" && $name!="Brian") {
  $error=true;
} else {
  $error=false;
}

With "in_array()"

$error=false;
if(!in_array($name, array('Allison', 'David', 'Brian')) {
  $error=true;
} else {
  $error=false;
}

With a "switch"

switch($name) {
  case 'Allison':
  case 'David':
  case 'Brian':
    $error=false;
    break;
  default:
    $error=true;
    break;
}

And I'm sure people can come up with more 😉

HTH
Bubble

[tuf-web_co_uk]

i had one but you got there before me :p

<?
$members = array("Allison", 
				"David",
				"Brian",
				"Eric",
				"Ben",
				"Mark",
				"Mike");

$error = TRUE;
$i=0;
while ($error) {

if ($name == $members[$i]) {
	$error = FALSE;
}
$i++;
}
?>

[bubblenut]

Bring it one! 😃
Binary Search

<?php
function binary_search($array, $value, $left, $right) {
    if($right<$left)
        return false;
    $mid = floor(($left+$right)/2);
    if($array[$mid] == $value)
        return true;
    elseif $value < $array[$mid]
        return binary_search($array, $value, $left, $mid-1);
    else
        return binary_search($array, $value, $mid+1, $right);
}

$members = array("Allison",
                "David",
                "Brian",
                "Eric",
                "Ben",
                "Mark",
                "Mike");

if(binary_search($members, $name, 0, count($members)))
    $error=false;
} else {
    $error=true;
}
?>

Just a joke really, I would have thought that the initial overhead would outway any possible gain. It's good fun though 😃

[dr0n3]

Great, thank you very much.