Converting ASP to PHP - clueless

watermelonkid

First of all, I don't know PHP. I'm just starting to learn.

That said, I have some ASP code that I'm using to force a "Save As" dialog box to open when I click a link to an MP3 in a Flash piece (so that the user can download the MP3 to where they want it).

I'm using a querystring to pass the file name/path information to the ASP page, with the variable "music".

How can I convert this ASP code to PHP, because I can't use ASP on with my hosting?

The ASP code is:

<%
const adTypeBinary = 1

	Dim sFileName
	sFileName = Request.QueryString("music")

	Dim objStream, body
	Set objStream = Server.CreateObject("ADODB.Stream")

	objStream.Type = adTypeBinary
	objStream.Open 
	objStream.LoadFromFile Server.MapPath(sFileName)
	body = objStream.Read

	objStream.Close
	set objStream = Nothing

	Response.AddHeader "content-disposition","inline; attachment; filename=" & chr(34) & sFileName & chr(34)     
	Response.ContentType = "application/octet-stream"
	Response.binarywrite body

Easy to do in PHP?

-watermelonkid

tsinka

Hi,

the following PHP code should do the same:

<?PHP
$sFilePath = $_GET["music"];
$sFileName = basename($sFilePath);
header("Content-Disposition: attachment; filename=\"$sFileName\"");

@readfile($sFilePath);
exit;
?>

Some additional headers might be neccessary but it should be sufficient for a little test.

Thomas

watermelonkid

Thanks. As of now, it's still not working on my server, and I think it's because I'm not using the right means to pass the variables.

I've tried both of these as the POST in Flash. Anyone know if this is right or wrong?

on (press) {
getURL("downloader.php?music=song.mp3");
}

OR this one, setting the variable elsewhere in Flash to
music = song.mp3;

on (press) {
loadVariables("downloader.php", 0, "POST");
}

tsinka

Hi,

if you post the data to the script you need to use $POST instead of $GET.

Use the following code to test your flash:

<?PHP
  if (isset($_POST) && is_array($_POST)) {
    print_r($_POST);
  }
  if (isset($_GET) && is_array($_GET)) {
    print_r($_GET);
  }
?>

This should print the get or post data in a readable way.

Thomas