[Resolved] getimagesize() does not return 'mime'

ppowell

According to the PHP manual (see http://us3.php.net/manual/en/function.getimagesize.php) I am supposed to be returned an associative array from getimagesize() with an element called 'mime':

$imgStatArray = @getimagesize("$locationPath/$imageFileName");
print_r($imgStatArray);

However, upon running this in my PHP 4.3.6 environment from the Ninth Circle of Hell I am getting this back:

imgStatArray: Array ( [0] => 768 [1] => 512 [2] => 3 [3] => width="768" height="512" )

I do, however, return the third element [2] which has the numerical index pointing to the MIME type (which I would love to figure out how on earth I'd get it from there!), but no 'mime'.

Any ideas?

Thanx
Phil

ppowell

		   if (is_array($imgStatArray) && @sizeof($imgStatArray) > 0) $imageMimeType = $imgStatArray['mime'];
		   /*---------------------------------------------------------------------------------------------------------------------------------------------
		     If 'mime' element is not found in the existing generated getimagesize() function return, use mime_content_type()
		     instead - this function is redefined in ../client_globals.inc.php
		   ----------------------------------------------------------------------------------------------------------------------------------------------*/
		   if (is_array($imgStatArray) && @sizeof($imgStatArray) > 0 && !$imageMimeType) $imageMimeType = mime_content_type("$locationPath/$fyl");

That is, if you have mime_content_type().

Phil