[Resolved] [Resolved] extract url from image source

viveleroi0

if I have a bit of code like:

<a href="image.php?File=/folder/image.gif"><img src="image_sm.gif">

How can I use php to pick out the "/folder/image.gif" portion?

planetsim

You may want to modify this i havent tested if this works or not but it should be something like you need

preg_match_all("/image.php?File=(.+?)/i",$string,$out);

viveleroi0

I tried using that code but I cannot figure out how to print it... I can just get "Array" printed again and again. How do I get the values out of the array? The manual does give two examples but they do not work.

Weedpacket

Originally posted by viveleroi0
The manual does give two examples but they do not work.

While it is possible that the manual has had buggy code for its examples for years without anyone noticing, it's more likely that your interpretation of their example code is faulty. But without seeing any of your code, it's impossible to tell how.

khjart

This will work

preg_match("/image.php\?File=([^\"]*)/i", $text, $out);
echo $out[1];

As you see, $out is an array, and the value of the key "1" is the what comes from the first set of brackets (after "File=").

viveleroi0

That does not work either. Here is my code:

$Extract_Prod	=	mysql_query("SELECT * FROM $Product_DB LIMIT 5");
$FroogleResult	=	mysql_num_rows($Extract_Prod);

		for($iFroogle = 0; $iFroogle < $FroogleResult; $iFroogle++)
			{
				$Froogle_row = mysql_fetch_array($Extract_Prod);
				$ProdName	=	$Froogle_row['ProdName'];
				$ProdImage	=	$Froogle_row['ProdImage'];
				$ProdPrice	=	$Froogle_row['ProdPrice'];
				$ID			=	$Froogle_row['ID'];

	preg_match("/image.php?File=([^\"]*)/i", $ProdImage, $out);
	echo $out[1];
	echo"$ProdName<br>";

			}

and I have also tried:

preg_match_all("/image.php?File=(.+?)/i", $ProdImage, $out);
echo $out[1];

The second bit of code writes the word "Array" to the page.

Now, I have displayed the other results using echo so that I know the results are coming back fine... there are no syntax errors or anything, it just comes out blank. The only thing I can think of is that the string I am seperating has double-quotes in it.

viveleroi0

I resolved this by using preg_split and then just analyzing the array for which out I wanted. Thanks anyway.