such and such are undeclared... but i did declare them...

c0d3m3

hey i new 2 here and php =) but this problem has been bothering me for about 2 weeks now and i cant continue learning php until i get this stupid error figured out. here it is.

i have the html file"form.html" like so:

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<title>Untitled Document</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
</head>

<body>

<?php
global $user;
global $address;
?>

</body>
</html>

then i have a php file"eg9.3.php" like so:

<html>
<head>
<title>php file</title>
</head>
<body>
<?

print "Welcome <b>$user</b><P>\n\n";
print "Your address is:<P>\n\n<b>$address</b>";
?>
</html>

and it either tells me that $user is undeclard same with $address
or nothing shows up at all...... why is this?
my 'books' all say that i can access the form names with php.. wuts going on wrong here? how can i make it work?
it should print out whatever $user and $address of the form is.

drew010

the
<?php
global $user;
global $address;
?>
is unnecessary. when forms are submitted, the fieldnames automatically become variables in the $_POST array. the keywork global is only used inside of functions that you want to have access certain variables.

one of the most basic form examples is this:

<?php
if ($_POST) {
  echo "Hello " . $_POST['name'];
} else {
  ?>
<form method="POST">
<input type="text" name="name"><br />
<input type="submit">
</form>
<?php
}
?>

c0d3m3

Sh*t that made me happy when it worked, thanx man 😉