$result = mysql_query($addfeedback); ???

[skimmer]

Sorry to be posting without having previously searching through de forum... but I really didn't knew what to look for.

I'm a newbie.. and I have been doing some toturials on PHP an MySQL... I found something that I consider very intriguing on one of the tuturials...

<?
#there's some code before this...

$db = mysql_connect("localhost");
	mysql_select_db("vinyldealers", $db);
	echo $db."<BR>";
	$addfeedback = "INSERT INTO feedback (user, email, spam, comments) VALUES('".$user."','".$email."','".$spam."','".$comments."')";
	echo $addfeedback;
	$result = mysql_query($addfeedback);
?>

(this is just the last part of the code, but it is probably enough)

How come this " $result = mysql_query($addfeedback); " makes the page work just fine? It successfully adds the entrys to the database... How come is the code executed if it is just placed on a variable? Shouldn't it only work only if the above line only contained " mysql_query($addfeedback); " How come is the variable executed???

Hope I made myself clear... probably not...

Thank you in advance, I really hope the question is not too dumb.

[thorpe]

the variable $addfeedback contains the SQL statement, its the SQL statement that is being executed.

this line assigns the $addfeedback variable the SQL statement:

$addfeedback = "INSERT INTO feedback (user, email, spam, comments) VALUES('".$user."','".$email."','".$spam."','".$comments."')";

[skimmer]

I guess I'm starting to figure it out...

I was looking at
$result = mysql_query($addfeedback);
And thinking I was seeing something like
$result = "mysql_query($addfeedback)";

Tnkx.. you've really helped me a lot understanding how the code works.

and the answer came really fast. gotta come to this forum more often. 😃