DB returns nuthing but count(!=0) still executes

[wirenot]

(See comlpete code at the end of post). Hi guys, I use the DB class to retrieve data from MySQL db and place it into the array. I want to run a different query dependnig if something is already in the DB or not. However, even if the $checkfeeds returns nothing checked in myphpadmin by just running

SELECT feed_id FROM news_feeds WHERE url = 'xxx'

the code inside

if (count($checkfeeds != 0))
{

	}

still executes. What gives? Helpppppppp!Thank you.

Full Code:

$checkfeeds =& $db->getAll("SELECT feed_id
FROM news_feeds
WHERE url = '$custom_feed5'",
array(), DB_FETCHMODE_ASSOC);

	if (count($checkfeeds != 0))
	{


	}

[laserlight]

The syntax should be:
if (count($checkfeeds) != 0)

assuming that your database wrapper does what you think it does.

[wirenot]

It works!!!!! THANK YOU SOOOOOOO MUCH!
I never knew one pair of ( ) can make such a difference.