why wont my variable update?

Jaycuse

I dont get it ... I have a variable who checks to see if I there is a cookie set :

if (!isset($_COOKIE['meter_user_name'])) { 
    $logged = false;
}
else {
    $logged = true;
}

And depending if the person is logged or not the it does stuff.

Like my login page, if he is already logged on it should show a message saying "You are already logged in!" and if he isint it should show the login form.

The problem I get is:
Lets say I login and go back to the login page it shows the form instead of the error message. And if I hit refresh, it fixs itself.

Can any one plz help me

edit: Any suggestions of were my error could be?

ZibingsCoder

When you say you "go back" to the login page...do you mean you press the back button? If so, you really can't do -too- much since a lot of browsers go back to a cached version of a page before loading a new version.

If that's not how you're going back...well actually, I still think this has to do with your browser caching things, but, let me know what else is happening if I'm wrong.

TheDefender

I know this may sound silly, but why not write the code so that if the user is not logged in, the link is a "Log In" link, and once they login, it turns into a "Log Out" link... I mean, if they are logged in, and still see a log in link, it could be confusing to the user, and a "Log In" page is useless to a user anyhow, if they are logged in already anyhow, right? (even if its sole purpose is to just tell the user they are already logged in)

Jaycuse

When I say go back to the login page I mean hit the link I have in the menu.

And to change it to a log out button will not help cuse it first need to pick up that i am logged in. Plus if im logged in there is a area that gets added that has a log out link. My problem is getting it to show at the right time.