[Resolved] simple include/constants/function issue

[commandonz]

I'm sure this is quite simple, but I haven't been able to work it out myself. Given the following code, and executing the test1main.php file, why doesn't the '3' get printed? All I get is 'const is' without the 3.

TIA 🙂

test1Main.php

<?php
   include_once('test1Include.php');
   include_once('test1Func.php');
   test();
?>

test1Include.php

<?php
   $const = 3;
?>

test1Func.php

<?php
   function test() {
      echo "const is {$const}";
   }
?>

[laserlight]

There is a scoping issue.

$const within test() is local to $test.

<?php
function test() {
   global $const;
   echo "const is {$const}";
}
?>

[commandonz]

wow, that's the fastest reply i've ever gotten on a forum, and answers my question perfectly 🙂

I have one follow up: is there any way to avoid having to use the "global" directive? ie predeclare a variable as global.

Perhaps if I didn't put the <?php> etc directives in the test1Include.php file would that do it? Seems unlikely but it's an idea...

[laserlight]

I have one follow up: is there any way to avoid having to use the "global" directive? ie predeclare a variable as global.

Yes, and it usually is preferred over global variables.
Pass the variable as an argument to the function, e.g.

function foo($bar) {
	echo "The \$bar argument has value '" . $bar . "'";
}

Perhaps if I didn't put the <?php> etc directives in the test1Include.php file would that do it? Seems unlikely but it's an idea...

No, include files that contain PHP code must have the PHP delimiters.

[commandonz]

Thanks laserlight 🙂 In return I shall try to help out people even newer than me 🙂