This should be a quickee :)

Dolemite50

Hi,
I am trying to do an email form for the first time. I am using checkboxes for the interests section with several checkboxes named int[] and am able to get the values from them fine if I do:

foreach($_POST['int'] as $value) {
echo $value , "\n";}

If I do that it will display the results.

My prob is that I dont want to display the results, I want to email them. How can I store them in a variable to send? I tried:

$interests = foreach($_POST['int'] as $value) {
echo $value , "\n";}

but it wouldnt let me.

I want to set the variable in another variable called $body_of_email

$body_of_email = "Followup form info: Email: $email 
Comments: $comments 
Interests: $value"; //THE INTEREST BOXES THEY CHECKED

I hope I explained this well enough, thanks for any help.

LordShryku

Check out [man]implode[/man]

$body_of_email = "Followup form info: 
<br><br> Email: $emai
<br>Comments: $comments";
if(isset($_POST['int'])) {
   $body_of_email .= "<br>".implode(', ' $_POST['int']);
}

move3rd

You can asgin the 'post' data to variables like this:

$my variable = $_POST['form_input_name'];

If you wanted all $post variables inside a sinlge variable you could do this:

foreach($_POST['int'] as $value) {
$value .= $value , "\n";}

--------- edit

looks the expert beat me to it...
With a better reply too

:eek:

Dolemite50

Thank you Lord.
heh

If anybody has a moment could you please explain that to me?

Thanks again everyone.

LordShryku

What do you need explained?

Dolemite50

Will I need to do

Interests: if(isset($POST['int'])) {
$body_of_email .= " ".implode(', ' $POST['int']);
}

(it needs to be after Interests: in an email. and I'm also ashamed to tell you that I've never seen "implode".

Also,..does ISSET just check to see if it has a value?

Thanks Mi' Lord.

LordShryku

isset just looks to see if the variable is set. It's just a check to say "if this variable exists, add it to the email body". I'd probably do more checking than that, like checking the [man]count[/man] of the array. To add the word "Interests" in there, here's what I would do...

$body_of_email = "Followup form info:
                  <br><br> Email: ".$email."
                  <br>Comments: ".$comments;
if(isset($_POST['int']) && is_array($_POST['int']) && count($_POST['int']) > 0) {
   $body_of_email .= "<br>Interests: ".implode(', ' $_POST['int']);
}

It says if $_POST['int'] is set and is an array and has elements, add it to the email body. You can look up the functions to see a better explaination on them....

Dolemite50

You are the man. Thanks for the speedy response, I'll give it a whirl.

Dolemite50

Ok bear with me Im as green as a horn gets.

Why in this line:
Email: ".$email." is it in quotes with a period before it? Is that to declare it a string? It worked ok with email: $email

The other thing that I dont get is on the first line, you set a variable with $body_of_email. Then on the last line (The condition for the if) you do $body_of_email = .
Wouldnt that change the whole $body_of_email variable? Or did you code it to add it to the existing?

Thanks again for your patience.

LordShryku

.= concatenates the strings. The period is the concatenation operator, so it says to just add this new stuff on the end of the original variable. The same applies with the variables being concatenated in the original string(the email part). It just concatenates the variables with the string. You'll eventually find a point where using a variable in a string doesn't work (arrays won't work), so it's a good habit to get into now.

Dolemite50

hmmmm,

I'm getting an error.
Parse error: parse error, unexpected T_VARIABLE in c:\wamp\www\contact.php on line 83

Here is my code. Note that the $body_of_email variable in this case translates to $content.

$content = "Followup form info: 
First Name: $fname 
Last Name: $lname 
Phone: $phone 
Cell: $cell 
Email: $email 
Comments: $comments";
if(isset($POST['int']) && is_array($POST['int']) && count($POST['int']) > 0) {
$content .= " Interests: ".implode(', ' $POST['int']);
}

This is line 83
$content .= " Interests: ".implode(', ' $_POST['int']);

Any idears?

LordShryku

Missing a comma...
implode(', ', $_POST['int'])

Dolemite50

BAM!!!!

Thank you so much man, I really appreciate it. Have yourself a good night.