variable of a variable

vavavince

hi peeps!!

i hav a set of variables taken from a form:

$id0=blah0
$id1=blah1
$id2=blah2
$id3=blah3
$id4=blah4

i want to make a loop in a way that it will display the value of the all the id's except the value of the the id which corresponds to the loop number.

loop 0 :
blah1blah2blah3blah4

loop 1 :
blah0blah2blah3blah4

loop 2 :
blah0blah1blah3blah4

and so on.. or actually to turn the unincluded variable to a zero.. hmm..

$id$i=0; ?????

some of my sample code?

echo '<td width=100> </td>';
$i=0;
while($i < $num)
{
echo '<td width=125>';
//$id[$i] = 0;
echo $id[$i];
echo $i.''." $id0 $id1 $id2 $id3 $id4 " ;
echo '</td>';
$i++;
}
echo '</tr>';

thanks in advance peeps.. more power!!!
😃

pete_bisby

First, have $id as an array:

$id[0] = "blah0";
$id[1] = "blah1";
 ...

Then, create your loop:

for ($i=0; $i < sizeof($id); $i++) {
  for ($j=0; $j < sizeof($id); $j++) {
    if ($i==$j) {
    } else {
      echo ...
    }
  }
}

vavavince

thanks i'll try that.. is there a way to input the contents of each array one by one from a form? i've tried to pass one, but how do i pass the values one by one and they all should be saved in the array $id[]?

this is what i've got so far..

<?php
$ii=0;

while(isset($arrayid[$ii]))
{
$ii++;

print $model.' ';
print $id;

$arrayid[$ii]= $id;
$arryamodel[$ii]= $model;

for ($i=1; $i<6; $i++)
{
print $arrayid[$i].' ';
print $arryamodel[$i].' '; //this is supposed to print the entire array

thanks for the help.. very much appreciated..
😃

Weedpacket

In the section on "Variables from outside PHP" in the manual, there are examples given that show how you can return an array from a form field; it amounts to using [] in the field names to specify array indices.