Is this possible to do?
I have a "description page" where you can see different features of an item. In this case, some items will show some "images" depending if they are linked by an URL through mySQL db.
http://localhost/mysite/images/image1.jpg for example
So depending if the column has the url of the image it will show, otherwise the value IS NULL.
Now, I put in my description page all the "img src" of all the images expecting to get all the images where they exist and excluding the ones that doesn´t exist for that item but I get always the "missing picture x" of the explorer where the values are NULL.
I have made this
$iconsr = mysql_db_query ("$DbName","SELECT * from icons WHERE IDres='$ID' AND IDres IS NOT NULL ");
Is there a way to exclude those images so they won`t show as missing?
Any help is greatly appreciated